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Harman [31]
3 years ago
7

To find the area, multiply the area of the entire circle by __?

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

3.142 × 6 = 18.852, thats : 19cm, then multiply 19 by 6 , so 19 would go in the square.

because area of a circle is p × r sq. u multiply one of the 6 by 3.142, you get 19, then multiply that 19 by the other 6. the answer is approximately 113.112.

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The solution of the given system of linear equations will lie in which of the following quadrants?
Rashid [163]

Answer: C Fourth Quadrant

Step-by-step explanation:

7 0
4 years ago
Last year, a popular song was downloaded 8.71 X 10^7 times. Write the number of
denis23 [38]

Answer:

Actually it would be 87,100,000 in standard form.

Step-by-step explanation:

3 0
3 years ago
The diagonal of a rectangular swimming pool measures 29 yards. If the length of the pool is 25 yards, which measurement is close
nirvana33 [79]

Answer:

Width of the pool = 15 yards

Step-by-step explanation:

Given that:

Length of diagonal of swimming pool = 29 yards

Length of the pool = 25 yards

Let,

w be the width.

This will form a right angled triangle where the diagonal will be hypotenuse.

Using Pythagorean theorem;

(25)^2+(w)^2 = (29)^2\\625+w^2=841\\w^2= 841 - 625\\w^2 = 216

Taking square root on both sides

\sqrt{w^2}=\sqrt{216}\\w=14.70

Rounding off to nearest whole number

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Hence,

Width of the pool = 15 yards

3 0
3 years ago
5 / 3 x + 1 / 3x equals 13 + 1 / 3 x + 8 / 3 x
NNADVOKAT [17]

Answer: x = - 12/9 ( the equation is negative)

Step-by-step explanation:

\frac{5}{3}x+\frac{1}{3}=13+\frac{1}{3}x+\frac{8}{3}x

\frac{5}{3}x=3x+\frac{38}{3}

\frac{5}{3}x-3x=3x+\frac{38}{3}-3x

-\frac{4}{3}x=\frac{38}{3}

3\left(-\frac{4}{3}x\right)=\frac{38\cdot \:3}{3}

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\frac{-4x}{-4}=\frac{38}{-4}

x=-\frac{19}{2}

8 0
3 years ago
Read 2 more answers
Complete these ordered pairs for this equation.<br> (0, ), (-1,), (1, ) y=2x+1<br> Help
N76 [4]

Answer:

(0, 1)

(-1, -1)

(1,3)

Step-by-step explanation:

Given the function;

y = 2x + 1

when x = 0

y = 2(0)+1

y = 1

Hence the required pair is (0, 1)

when x = -1

y = 2(-1) + 1

y = -2 + 1

y = -1

Hence the coordinate is (-1, -1)

when x = 1

y = 2(1) + 1

y = 2 + 1

y =3

Hence the coordinate is (1, 3)

7 0
3 years ago
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