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Harman [31]
2 years ago
7

To find the area, multiply the area of the entire circle by __?

Mathematics
1 answer:
Elan Coil [88]2 years ago
5 0

Answer:

3.142 × 6 = 18.852, thats : 19cm, then multiply 19 by 6 , so 19 would go in the square.

because area of a circle is p × r sq. u multiply one of the 6 by 3.142, you get 19, then multiply that 19 by the other 6. the answer is approximately 113.112.

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Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to
dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} =  (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500})  = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

4 0
2 years ago
MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!!
Blizzard [7]
ive forgotten the method
4 0
3 years ago
Which one pls help me
vampirchik [111]

Answer:

C

Step-by-step explanation:

If one answer is longer then the others, Then that's the correct answer

5 0
2 years ago
Read 2 more answers
A teacher asked each of his students how many books were read during the summer. Which histogram accurately displays this data?
devlian [24]

Answer:

The frequency distribution is given below:

Class                      Frequency

0 - 9                               9

10 - 19                             6

20 - 29                           3

30 - 39                           3

40 - 49                           3

From the given 4 options, the histogram in option A accurately displays this data. Hence the option A is correct.



6 0
3 years ago
Read 2 more answers
A manufacturer knows that their items have a normally distributed lifespan, with a mean of 15 years, and standard deviation of 3
Gala2k [10]

Answer:

The probability that their mean life will be longer than 13 years = .9943 or 99.43%

Step-by-step explanation:

Given -

Mean (\nu  ) = 15 years

Standard deviation (\sigma  ) = 3.7 years

Sample size ( n ) =22

Let \overline{X} be the mean life of manufacturing items

the probability that their mean life will be longer than 13 years =

P(\overline{X}>  13) =  P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}>  \frac{13 - 15 }{\frac{3.7}{\sqrt{22}}})       (Z =\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}})

                    =  P(Z> -2.53)

                    = 1 - P(Z <  -2.53)       Using Z table

                    = 1 - .0057

                    =  .9943

7 0
3 years ago
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