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ANTONII [103]
3 years ago
5

Compare & contrast the graphs of y = 5x+9 and y - 5x=3

Mathematics
1 answer:
arlik [135]3 years ago
3 0
They both run diagonally (compare)...
the <span>y = 5x+9 is moved 6 points to the left
</span>
hope it works
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Stein Co. issued 13-year bonds two years ago at a coupon rate of 10.3 percent. The bonds make semiannual payments. If these bond
Firlakuza [10]

Nper = 11*2 = 22 (indicates the period over which interest payments are made)

PMT = 1000*10.3%*1/2 = 51.5 (indicates sem-annual interest payments)

PV = 1000*95% = 950 (indicates the current selling price of the bonds)

FV = 1000 (indicates the face value of bonds)

Rate = ? (Indicates YTM)


YTM = Rate(Nper,PMT,PV,FV)*2 = Rate(22,51.5,-950,1000)*2 = 11.098% or 11.10%


Answer is 11.098% or 11.10%.

4 0
3 years ago
Find dy/dx for 4 - xy = y^3
storchak [24]

Answer:

\frac{dy}{dx}=-\frac{y}{3y^2+x}

Step-by-step explanation:

4-xy=y^3

dy/dx=?

\frac{d(4-xy)}{dx}=\frac{d(y^3)}{dx}\\ \frac{d(4)}{dx}-\frac{d(xy)}{dx}=3y^{3-1}\frac{dy}{dx}\\ 0-(\frac{dx}{dx}y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(1y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -y-x\frac{dy}{dx}=3y^2\frac{dy}{dx}

Solving for dy/dx: Addind x dy/dx both sides of the equation:

-y-x\frac{dy}{dx}+x\frac{dy}{dx}=3y^2\frac{dy}{dx}+x\frac{dy}{dx} \\ -y=3y^2\frac{dy}{dx}+x\frac{dy}{dx}

Common factor dy/dx on the right side of the equation:

-y=(3y^2+x)\frac{dy}{dx}

Dividing both sides of the equation by 3y^2+x:

\frac{-y}{3y^2+x}=\frac{(3y^2+x)}{3y^2+x}\frac{dy}{dx}\\ -\frac{y}{3y^2+x}=\frac{dy}{dx}\\ \frac{dy}{dx}=-\frac{y}{3y^2+x}

7 0
3 years ago
MR MARK MARKS HIS CLASS ON A NORMAL CURVE. THOSE WITH z-SCORES ABOVE 1.8 WILL RECEIVE AN A, THOSE
lukranit [14]

Using the normal distribution, it is found that the percentages are given as follows:

  • 3.59% of the grades will be A.
  • 9.98% of the grades will be B.
  • 74.92% of the grades will be C.
  • 8.64% of the grades will be D.
  • 2.87% of the grades will be F.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The prorportion of students who receive an A is <u>one subtracted by the p-value of Z = 1.8</u>.

Looking at the z-table, Z = 1.8 has a p-value of 0.9641.

1 - 0.9641 = 0.0359.

3.59% of the grades will be A.

For B, it is the <u>p-value of Z = 1.8 subtracted by the p-value of Z = 1.1</u>, hence:

0.9641 - 0.8643 = 0.0998.

9.98% of the grades will be B.

For C, it is the <u>p-value of Z = 1.1 subtracted by the p-value of Z = -1.2</u>, hence:

0.8643 - 0.1151 = 0.7492.

74.92% of the grades will be C.

For D, it is the <u>p-value of Z = -1.2 subtracted by the p-value of Z = -1.9</u>, hence:

0.1151 - 0.0287 = 0.0864.

8.64% of the grades will be D.

For F, it is the <u>p-value of Z = -1.9</u>, hence 2.87% of the grades will be F.

More can be learned about the normal distribution at brainly.com/question/15181104

#SPJ1

7 0
1 year ago
10.6 written as a decimal and a fraction or a mixed number in simplest form
lakkis [162]
10.6 \times \frac{10}{10} = \frac{106}{100} = \frac{53 \times 2}{50\times 2} \\\\ = \frac{53}{50} = \boxed{\bf{1 \frac{3}{50}}}

and 10.6 is already written as a decimal.
6 0
3 years ago
Please help will mark brainliest
asambeis [7]

The total cost of the tent is 409.86

------------------------------------------------------

explanation:

230×0.65=149.50

230+149.50=379.50×.08=30.36

379.50+30.36=409.86

(Hope this helps :) )

5 0
2 years ago
Read 2 more answers
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