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3 years ago

Compare & contrast the graphs of y = 5x+9 and y - 5x=3

Mathematics

1 answer:

arlik [135]3 years ago

3 0

They both run diagonally (compare)...
the y = 5x+9 is moved 6 points to the left

hope it works

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Stein Co. issued 13-year bonds two years ago at a coupon rate of 10.3 percent. The bonds make semiannual payments. If these bond

Firlakuza [10]

Nper = 11*2 = 22 (indicates the period over which interest payments are made)

PMT = 1000*10.3%*1/2 = 51.5 (indicates sem-annual interest payments)

PV = 1000*95% = 950 (indicates the current selling price of the bonds)

FV = 1000 (indicates the face value of bonds)

Rate = ? (Indicates YTM)

YTM = Rate(Nper,PMT,PV,FV)*2 = Rate(22,51.5,-950,1000)*2 = 11.098% or 11.10%

Answer is 11.098% or 11.10%.

4 0

3 years ago

Find dy/dx for 4 - xy = y^3

storchak [24]

Answer:

$\frac{dy}{dx}=-\frac{y}{3y^2+x}$

Step-by-step explanation:

4-xy=y^3

dy/dx=?

$\frac{d(4-xy)}{dx}=\frac{d(y^3)}{dx}\\ \frac{d(4)}{dx}-\frac{d(xy)}{dx}=3y^{3-1}\frac{dy}{dx}\\ 0-(\frac{dx}{dx}y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(1y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -y-x\frac{dy}{dx}=3y^2\frac{dy}{dx}$

Solving for dy/dx: Addind x dy/dx both sides of the equation:

$-y-x\frac{dy}{dx}+x\frac{dy}{dx}=3y^2\frac{dy}{dx}+x\frac{dy}{dx} \\ -y=3y^2\frac{dy}{dx}+x\frac{dy}{dx}$

Common factor dy/dx on the right side of the equation:

$-y=(3y^2+x)\frac{dy}{dx}$

Dividing both sides of the equation by 3y^2+x:

$\frac{-y}{3y^2+x}=\frac{(3y^2+x)}{3y^2+x}\frac{dy}{dx}\\ -\frac{y}{3y^2+x}=\frac{dy}{dx}\\ \frac{dy}{dx}=-\frac{y}{3y^2+x}$

7 0

3 years ago

MR MARK MARKS HIS CLASS ON A NORMAL CURVE. THOSE WITH z-SCORES ABOVE 1.8 WILL RECEIVE AN A, THOSE

lukranit [14]

Using the normal distribution, it is found that the percentages are given as follows:

3.59% of the grades will be A.

9.98% of the grades will be B.

74.92% of the grades will be C.

8.64% of the grades will be D.

2.87% of the grades will be F.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The prorportion of students who receive an A is one subtracted by the p-value of Z = 1.8.

Looking at the z-table, Z = 1.8 has a p-value of 0.9641.

1 - 0.9641 = 0.0359.

3.59% of the grades will be A.

For B, it is the p-value of Z = 1.8 subtracted by the p-value of Z = 1.1, hence:

0.9641 - 0.8643 = 0.0998.

9.98% of the grades will be B.

For C, it is the p-value of Z = 1.1 subtracted by the p-value of Z = -1.2, hence:

0.8643 - 0.1151 = 0.7492.

74.92% of the grades will be C.

For D, it is the p-value of Z = -1.2 subtracted by the p-value of Z = -1.9, hence:

0.1151 - 0.0287 = 0.0864.

8.64% of the grades will be D.

For F, it is the p-value of Z = -1.9, hence 2.87% of the grades will be F.

More can be learned about the normal distribution at brainly.com/question/15181104

#SPJ1

7 0

1 year ago

10.6 written as a decimal and a fraction or a mixed number in simplest form

lakkis [162]

$10.6 \times \frac{10}{10} = \frac{106}{100} = \frac{53 \times 2}{50\times 2} \\\\ = \frac{53}{50} = \boxed{\bf{1 \frac{3}{50}}}$

and 10.6 is already written as a decimal.

6 0

3 years ago

Please help will mark brainliest

asambeis [7]

The total cost of the tent is 409.86

------------------------------------------------------

explanation:

230×0.65=149.50

230+149.50=379.50×.08=30.36

379.50+30.36=409.86

(Hope this helps :) )

5 0

2 years ago

Read 2 more answers