Question

A skyscraper casts a shadow 200 feet long. If the angle of elevation of the sun is 49 , then the height of the skyscraper is _____.

Answer 1

Answer:

Height of the skyscraper = 230.07 feet

Step-by-step explanation:

In the given triangle AB is a skyscraper that casts a shadow of 200 feet long.

If the angle of elevation of the sun is 49°

In the given right angle triangle ABC

tanC = $\frac{AB}{BC}$

$tan49=\frac{AB}{200}$

AB = 1.1504×200

     = 230.07 feet

Therefore, the height of the skyscraper is 230.07 feet

Answer 2

Based on the information, you could find it using this formula :

Assuming the height of the skyscraper is coded as 'y'

Tan 49 = y/200

1.1504 = y/200

y = 230.8 Feet

hope this helps