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viktelen [127]
3 years ago
11

The nicotine content in a single cigarette of a particular brand has a distribution with mean 0.4 mg and standard deviation 0.1

mg. If 100 randomly selected cigarettes of this brand are analyzed, what is the probability that the resulting sample mean nicotine content will be less than 0.38
Mathematics
1 answer:
a_sh-v [17]3 years ago
8 0

Answer:

Step-by-step explanation:

For this case we can define the random variable of interest as: "The nicotine content in a single cigarette " and for this case we know the following parameters:

\mu = 0.4, \sigma = 0.1

And for this case we select a sample size of n =100 and we want to find the following probability:

P(\bar X

And for this case we can use the z score formula given by:

z =\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z= \frac{0.38-0.4}{\frac{0.1}{\sqrt{100}}}= -2

And we can find the required probability with the normal standard table and we got:

P(z

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monitta

The solution of the equation x2+7x​ is 0, -7 using the quadratic formula.

Step-by-step explanation:

x2 + 7x = 0

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substitution,

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= -7  ± √(7)2 - 4(1 x 0) / 2 x 1

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The temperature is -5°C at sunrise. By noon, the temperature changes by 6°C what could be the temperature at noon? answer asap !
Citrus2011 [14]

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Step-by-step explanation:

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Look at the picture below for more detail
guapka [62]

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Step-by-step explanation:

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rosijanka [135]

Answer:

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