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3 years ago

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The vertex of this parabola is at (-3,2). Which of the following could be its equation?

2 answers:

VashaNatasha [74]3 years ago

7 0

vertex form of a parabola

y= a(x-h)^2 +k

y =a(x--3)^2 +2

y = a(x+3)^2 +2

Choice B

Gnoma [55]3 years ago

5 0

Answer:

The answer is B.

Step-by-step explanation:

When you have an equation in vertex form, we can find the x value of the vertex by looking in the parenthesis. The opposite number as is being added to x is the x value. Since we are looking for -3, we are looking for a positive 3 in the parenthesis. This leaves us with just A and B.

On the outside, the constant is the y value of the vertex. Since we are looking for a positive 2, we know B is the correct choice.

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1 _ 5,504 is divisible by 3

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Answer:

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Step-by-step explanation:

The trick to know if a number is divisible by three or not is to

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What is1.125 as a fraction?

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Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2

Anastaziya [24]

Answer:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

Step-by-step explanation:

we would like to figure out the derivative of the following:

$\displaystyle \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

to do so, let,

$\displaystyle y = \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

By simplifying we acquire:

$\displaystyle y = 3 - \frac{2}{x} - \frac{1}{ {x}^{2} }$

use law of exponent which yields:

$\displaystyle y = 3 - 2 {x}^{ - 1} - { {x}^{ - 2} }$

take derivative in both sides:

$\displaystyle \frac{dy}{dx} = \frac{d}{dx} (3 - 2 {x}^{ - 1} - { {x}^{ - 2} } )$

use sum derivation rule which yields:

$\rm\displaystyle \frac{dy}{dx} = \frac{d}{dx} 3 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

By constant derivation we acquire:

$\rm\displaystyle \frac{dy}{dx} = 0 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

use exponent rule of derivation which yields:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ - 1 -1} ) - ( - 2 {x}^{ - 2 - 1} )$

simplify exponent:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ -2} ) - ( - 2 {x}^{ - 3} )$

two negatives make positive so,

$\displaystyle \frac{dy}{dx} = 2 {x}^{ -2} + 2 {x}^{ - 3}$

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

$\displaystyle \frac{dy}{dx} = \frac{2 }{x^2}+ \frac{2}{x^3}$

simplify addition:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

and we are done!

5 0

3 years ago

What is 1 plus 1. thanks for the help on my 21th grade math

almond37 [142]

1 plus 1 is 100, welcome <3

4 0

3 years ago