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Andreas93 [3]
3 years ago
10

Suppose a population of 250 crickets doubles in size every 6 months. How many crickets will there be after 2 years?

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
8 0

For this case we have a function of the form:

y = A * (b) ^ x

Where,

A: initial value

b: growth rate

x: time in months

Rewriting the equation we have:

y = 250 * (2) ^ {(\frac{1}{6} * x)}

When 2 years pass, we have 24 months.

Therefore, substituting the value of x = 24 in the given equation we have:

y = 250 * (2) ^ {(\frac{1}{6} * 24)}\\y = 4000

Answer:

there will be 4000 crickets after 2 years

lawyer [7]3 years ago
7 0
If a population of 250 crickets doubles in size every 6 months, there will be approximately 4,000 crickets in 2 years. 
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Answer:

0.33

Step-by-step explanation:

Let A denote an event. The odds of the horse finishing second is 33 to 67.

From the information, the total outcomes of event A is:

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Hence, there are 100 total outcomes. The probability of the horse finishing second is calculated as:

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3 years ago
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pychu [463]

Given:

The figure of a rhombus QRST.

To find:

A. The value of x.

B. The measure of angle RQP.

Solution:

A. We need to find the value of x.

We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.

m\angle RPS=90^\circ                       [Right angle]

(5x+15)^\circ=90^\circ

(5x+15)=90

5x=90-15

5x=75

Divide both sides by 5.

x=\dfrac{75}{5}

x=15

Therefore, the value of x is 15.

B. We need to find the measure of angle RQP.

From the given figure, it is clear that

m\angle RQP=(2x+3)^\circ

Putting x=15, we get

m\angle RQP=(2(15)+3)^\circ

m\angle RQP=(30+3)^\circ

m\angle RQP=33^\circ

Therefore, the measure of angle RQP is 33 degrees.

8 0
3 years ago
12598 round to the nearest thousand
MakcuM [25]
12598 rounded to the nearest thousands is 1260
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antiseptic1488 [7]

Answer:

From the answers you provided the best answer is B.52

Step-by-step explanation:

It starts past 32 so there's no way it can ever be that value as the graph is continuously increasing.

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AVprozaik [17]
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