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2 years ago

- find the volume of this cylinder diameter = 6 cm height = 11 cm

Mathematics

1 answer:

ValentinkaMS [17]2 years ago

6 0

the cylinders volume is 99pie

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your teacher is giving you a test with 100 points containing 40 questions. there are two point and four point questions on the t

tino4ka555 [31]

Answer:

30 of 2 points= 60 points

10 of 4 points = 40points so its 30 of 2 points and 10 of 4

Step-by-step explanation:

5 0

2 years ago

Find the volume of this cone.

Katen [24]

Answer:

...... here.....

ghChfahgahat htahath twj wtu wt htw h wth wth wt hw fjw tj taj wth th wt hwt hwt th wth

needed to be 20 characters long so......

3 0

3 years ago

Which recursive formula can be used to generate the sequence shown, where f(1) = 5 and n > 1?

saveliy_v [14]

You can try them out and see which one works.

a: f(2) = f(1) +6 = 5+6 = 11 . . . . . . not this one

b: f(1) = f(2) -6 = -1-6 = -7 . . . . . . not this one (5 ≠ -7)

c: f(2) = f(1) - 6 = 5 - 6 = -1 . . . . . this gives the right f(2)

d: f(2 = -6(f(1) = -6(5) = -30 . . . . not this one

_____

The appropriate choice is ...

... f(n +1) = f(n) - 6

— — — — —

You can also recognize that the next term is 6 less than the current one, so f(n+1) = f(n) - 6, which corresponds to the 3rd selection.

7 0

2 years ago

Read 2 more answers

A rectangle has a length of (x+10) centimeters and a width of x centimeters. If the perimeter is 32 centimeters, what is the len

I am Lyosha [343]

Given:

Length of rectangle = (x+10) cm

Width of the rectangle = x cm

Perimeter = 32 cm

To find:

The length of the rectangle.

Solution:

We know that,

$Perimeter=2(l+w)$

Where, l is length and w is width.

Substituting the values, we get

$32=2((x+10)+x)$

$32=2(2x+10)$

$32=4x+20$

Subtract 20 from both sides.

$32-20=4x$

$12=4x$

Divide both sides by

$3=x$

So, the length is

$3+10=13$

Therefore, the length of the rectangle is 13 cm.

7 0

2 years ago

Solve |x – 4| + 6 = 17.

const2013 [10]

Answer:

$\mathrm{C)\:}x=15,\:-7$

Step-by-step explanation:

For $|a-b|=c$ , there are two possible cases:

$\begin{cases}a-b=c\\a-b=-c\\\end{cases}$

Solving for both cases, we get:

$\begin{cases}x-4+6=17, \:x+2=17, \: \fbox{$x=15$}\\-(x-4)+6=17,\: -x+10=17, \: -x=7, \:, \fbox{$x=-7$}\\\end{cases}$

6 0

2 years ago