Let's solve this problem step-by-step.
STEP-BY-STEP SOLUTION:
To begin with, let's establish that ( x ) can equal to any number from 0 to 9.
Meaning, that ( x ) is equal to one of the following: 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9.
Now that we know which values ( x ) can equal to, we will simply substitute each of the numbers as potential values of ( x ) into the six-digit number and divide it by 27 to see if it is a multiple of 27.
If X = 0
= 63X904 / 27
= 630904 / 27
= Not a whole number
Therefore, X is not equal to 0.
If X = 1
= 63X904 / 27
= 631904 / 27
= Not a whole number
Therefore, X is not equal to 1.
If X = 2
= 63X904 / 27
= 632904 / 27
= Not a whole number
Therefore, X is not equal to 2.
If X = 3
= 63X904 / 27
= 633904 / 27
= Not a whole number
Therefore, X is not equal to 3.
If X = 4
= 63X904 / 27
= 634904 / 27
= Not a whole number
Therefore, X is not equal to 4.
If X = 5
= 63X904 / 27
= 635904 / 27
= 23552
ANSWER:
Therefore, the answer is:
X = 23, 552
Please mark as brainliest if you found this helpful! :)
Thank you <3
Answer:
Step-by-step explanation:
Hypotenuse = x
Base = 4
Perpendicular = 
<u>Using Pythagoras Theorem:</u>
![\sf H^2 = P^2 + B^2\\\\ x^2 = (\sqrt{84} )^2 + (4)^2\\\\x^2 = 84 + 16\\\\x^2 = 100\\\\Taking \ sq \ root \ on \ both \ sides\\\\x = 10\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20H%5E2%20%3D%20P%5E2%20%2B%20B%5E2%5C%5C%5C%5C%20x%5E2%20%3D%20%28%5Csqrt%7B84%7D%20%29%5E2%20%2B%20%284%29%5E2%5C%5C%5C%5Cx%5E2%20%3D%2084%20%2B%2016%5C%5C%5C%5Cx%5E2%20%3D%20100%5C%5C%5C%5CTaking%20%5C%20sq%20%5C%20root%20%5C%20on%20%5C%20both%20%5C%20sides%5C%5C%5C%5Cx%20%3D%2010%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
It would be: 11 1/9 = 100/9
So, Your Final Answer would be 100/9
Hope this helps!
Answer:
$2.34
Step-by-step explanation:
2.75 (the number of pounds) * 0.85 (price per pound) = 2.3375, or approximately 2.34.
If you divide both 9 and 15 by 3, you can see that the ratio of 9/15 is 3/5
