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gavmur [86]
4 years ago
13

Mrs. Harrison has a jar full of cookies.

Mathematics
2 answers:
Dafna11 [192]4 years ago
5 0
C
12 divided by 4 is 3
Therefore there are 4 groups of 3
Elanso [62]4 years ago
4 0

Answer:

C

Step-by-step explanation:

12 oatmeal cookies divided by 3 sugar cookies is 4. AKA there are 4 groups of 3.

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Please help >.<
alukav5142 [94]

Answer:

The Fox and The Grapes Story in English

One afternoon, a fox which was out for a walk in the jungle came across a bunch of grapes hanging. Its mouth watered at the very sight of the grapes. ... It jumped high to reach the bunch of grapes but failed. It tried again and again, but the fox missed it each time.Oct 16, 2019

7 0
3 years ago
Read 2 more answers
Suppose you just purchased a digital music player and have put 15 tracks on it. After listening to them you decide that you like
blsea [12.9K]

Answer:

Total songs = 15

Liked songs = 3

Un liked songs = 15-3=12

Find the probability that among the first two songs played

​(a) You like both of them.

Probability that among the first two songs played you like both of them = \frac{3}{15} \times \frac{2}{14} = 0.029

​(b) You like neither of them.

Probability that among the first two songs played you like neither of them = \frac{12}{15} \times \frac{11}{14} = 0.629

​(c) You like exactly one of them.

Probability that among the first two songs played you like exactly one of them = \frac{3}{15} \times \frac{12}{14}+ \frac{12}{15} \times \frac{3}{14}= 0.343

(d) Redo​ (a)-(c) if a song can be replayed before all

​(a) You like both of them. Would this be​ unusual?

Probability that among the first two songs played you like both of them = \frac{3}{15} \times \frac{3}{15} = 0.04

​(b) You like neither of them.

Probability that among the first two songs played you like neither of them = \frac{12}{15} \times \frac{12}{15} = 0.64

​(c) You like exactly one of them.

Probability that among the first two songs played you like exactly one of them = \frac{3}{15} \times \frac{12}{15}+ \frac{12}{15} \times \frac{3}{15}= 0.32

7 0
4 years ago
a small jet can fly 1,435 miles in 5 hours with a tailwind but only 1,215 miles in 5 hours into a headwind. find the speed of th
Ne4ueva [31]

Answer:

Speed of Jet in Still Air = 265 miles per hour

Speed of Wind = 22 miles per hour

Step-by-step explanation:

Let x be speed of jet

and c be speed of wind

We know D = RT, where

D is distance

R is rate

T is time

For first leg:

1435 miles in 5 hours, the rate is:

Rate = 287 mph

For second leg:

1215 miles in 5 hours, the rate is:

Rate = 243 mph

So 287 is with wind and 243 against wind, thus we can write:

x + c = 287

x - c = 243

Adding gives us:

2x = 530

x = 265 miles per hour [still rate]

Speed of wind:

x + c = 287

265 + c = 287

c = 22 miles per hour [speed of wind]

4 0
3 years ago
Get brainiest if right?
aev [14]

Answer:

30 mph

Step-by-step explanation:

train stopped after 520 miles

780 miles to go

stopped at 20 hours

stopped for 4 hours

34 hours used up...

26 hours left

780 miles to go

780 miles/26 hrs = 30 m/hr

5 0
3 years ago
8. To calculate 159 - 73, a student writes the follow-
Evgen [1.6K]

The question is an illustration of solving equations using estimates.

The student's strategy makes sense because he uses estimation to solve the given equation

The correct sequence of equation is as follows:

  • \mathbf{159 - 73}
  • \mathbf{159 - 73 =160 - 70- 1 - 3}
  • \mathbf{159 - 73 =90- 4}
  • \mathbf{159 - 73 =86}

We have:

\mathbf{159 - 73}

Add 0 to the equation

\mathbf{159 - 73 =159 + 0- 73}

Express 0 as 1 - 1

\mathbf{159 - 73 =159 + 1 - 1- 73}

\mathbf{159 - 73 =160 - 1- 73}

Add another 0

\mathbf{159 - 73 =160 - 1- 73 + 0}

Express 0 as 3 - 3

\mathbf{159 - 73 =160 - 1- 73 + 3 - 3}

\mathbf{159 - 73 =160 - 1- 70 - 3}

Rewrite as:

\mathbf{159 - 73 =160 - 70- 1 - 3}

Solve

\mathbf{159 - 73 =90- 4}

\mathbf{159 - 73 =86}

Read more about estimation and equations at:

brainly.com/question/18454732

7 0
3 years ago
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