Question

I need help with 1-3 please and help!

Answer 1

Answer:

Q : 3

10x - 11 = 120 - 11 = 109°

 3x - 2    = 36 - 2  = 34°

 3x + 1     = 36 + 1  = 37°

Q ; 2

3x - 5 = 27 - 5= 22°

7x + 5 = 63 + 5 = 68°

And 90°

Q1 :

∠1 = 92°

∠2 = 42°

∠3 =  113°

Step-by-step explanation:

Solution for Q : 3

As the angle of all three is given as ,

10x - 11

3x - 2

3x + 1

We know sum of all the three angles of triangle = 180 °

So, (10x - 11) + (3x - 2) + (3x + 1) = 180°

Or,   16x - 12 = 180°

Or     16x = 192°, So    , x = 12

So, all three angles are 10x - 11 = 120 - 11 = 109°

                                       3x - 2    = 36 - 2  = 34°

                                       3x + 1     = 36 + 1  = 37°

Solution for Q - 2

Given angles are

3x - 5

7x + 5

90°

We know sum of all the three angles of triangle = 180 °

so ,(3x - 5) + (7x + 5) + 90 = 180°

or 10x  =                       180 - 90 = 90°

SO, x = 9°

SO, all the three angles are 3x - 5 = 27 - 5= 22°

                                              7x + 5 = 63 + 5 = 68°

And                                                                    90°

Solution for Q : 1

From,

the shown fig it is clear that

The ∠2 = 42°      ( opposite vertical angles )

so, in  left triangle

50° + ∠2 + ∠1  = 180°

Or,  50° + 42° + ∠1 = 180°     ( sum of all angles of triangles = 180°)

Or, ∠1 = 92°

 Again

From right figure triangle

∠2 + 25° + ∠3 = 180°

Or, 42° + 25° + ∠3 = 180

Or, ∠3 = 113°