Answer:
I'm not entirely sure but I think that what is says is that it wants you to find the value of x in (4x+28) to make it 116 degrees because it is that same angle. So what you do is you get (4x+28)=116 and you do this because they are the same angle so you use 116 and get it to solve x. Since I'm lazy, then I go to this website and type the equation in: m a t h w a y . c o m but without all of the spaces, I had to do that so it would let me answer this, but I'll do it the real way this time. (4x+28)=116 Their is a rule in math that as long as you do something to one side of the equal sign in the equation, you have to do it to the other and it will still work. So, you minus 28 from both sides so that you can get rid of it and you now have 4x=88. Now you should know this part but you divide 4 from both sides to make so x is alone. Now you have x=22 because you divided 4 from each side. So their is your answer: x=22.
Step-by-step explanation: If you have the answer key that you can check from to make sure you got it right because I know some teachers let you do that, then you should make sure that is right, but I am pretty sure it is.
Answer:
The probability that on any given day the water supply is inadequate 
Step-by-step explanation:
Given
α = 2 and β = 3
As per Gamma distribution Function
Expanding the function and putting the given values, we get -
![[tex]1 - \int\limits^9_0 {f(x;2,3)} \, dx \\1- \int\limits^0_0 {\frac{1}{9}xe^{\frac{-x}{3} } \, dx\\\\= 1- \frac{1}{9} [x(-3e^{\frac{-x}{3}}) -\int\limits {(-3e^{\frac{-x}{3}})} \, dx]^9_0= 1- 1/9 [x(-3e^{\frac{-x}{3}}) -9e^{\frac{-x}{3}})} \, dx]^9_0\\1-((\frac{-1}{3} *9*e^({\frac{-9}{3}})- e^(\frac{-9}{3}))- ((\frac{-1}{3} *0*e^(\frac{-9}{3})-e^{\frac{-0}{3}})\\1-((-3e^{\frac{-9}{3} }-e^{\frac{-9}{3}}-(0-1))\\1-(1-4e^{-3})\\1-(1-0.1991)\\1-0.8009\\0.1991](https://tex.z-dn.net/?f=%5Btex%5D1%20-%20%5Cint%5Climits%5E9_0%20%7Bf%28x%3B2%2C3%29%7D%20%5C%2C%20dx%20%5C%5C1-%20%5Cint%5Climits%5E0_0%20%7B%5Cfrac%7B1%7D%7B9%7Dxe%5E%7B%5Cfrac%7B-x%7D%7B3%7D%20%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D%201-%20%5Cfrac%7B1%7D%7B9%7D%20%5Bx%28-3e%5E%7B%5Cfrac%7B-x%7D%7B3%7D%7D%29%20-%5Cint%5Climits%20%7B%28-3e%5E%7B%5Cfrac%7B-x%7D%7B3%7D%7D%29%7D%20%5C%2C%20dx%5D%5E9_0%3D%201-%201%2F9%20%5Bx%28-3e%5E%7B%5Cfrac%7B-x%7D%7B3%7D%7D%29%20-9e%5E%7B%5Cfrac%7B-x%7D%7B3%7D%7D%29%7D%20%5C%2C%20dx%5D%5E9_0%5C%5C1-%28%28%5Cfrac%7B-1%7D%7B3%7D%20%2A9%2Ae%5E%28%7B%5Cfrac%7B-9%7D%7B3%7D%7D%29-%20e%5E%28%5Cfrac%7B-9%7D%7B3%7D%29%29-%20%28%28%5Cfrac%7B-1%7D%7B3%7D%20%2A0%2Ae%5E%28%5Cfrac%7B-9%7D%7B3%7D%29-e%5E%7B%5Cfrac%7B-0%7D%7B3%7D%7D%29%5C%5C1-%28%28-3e%5E%7B%5Cfrac%7B-9%7D%7B3%7D%20%7D-e%5E%7B%5Cfrac%7B-9%7D%7B3%7D%7D-%280-1%29%29%5C%5C1-%281-4e%5E%7B-3%7D%29%5C%5C1-%281-0.1991%29%5C%5C1-0.8009%5C%5C0.1991)
The probability that on any given day the water supply is inadequate
<span>We will use s for the cost of a small candle and m for the cost of a medium candle.
(a)
The candles and price for Jin can be written as:
3s+1m=$3.85
The candles and price for Trish can be written as:
4s+5m=$10.45
The system of equations that we have is:
</span>3s+1m=$3.85
4s+5m=$10.45
(b)
We will use substitution to solve this problem.
From the first equation we can find out m:
3s+1m=$3.85
1m=$3.85-3s
Now we insert this into second equation and we solve it for s:
4s+5($3.85-3s)=$10.45
4s+$19.25-15s=$10.45
-11s=-8.8
s=$0.8
Now we can find m:
m=$3.85-3*$0.8
m=$3.85-$2.4
m=$1.45
(c)
The candles and price for Jin can be written as:
2s+1m=price
We can insert values for s and m:
2*$0.8+$1.45=price
price=$1.6+$1.45
price=$3.05
10:12
15:18
i got this from doubling the first to make 5 = 10 and then that made 6 = 12. the second one was the same but tripled to make 6 = 18 and then that made 5 = 15
Answer:
Y has to belong to the interval [-9,-2]
Step-by-step explanation:
-9≤y≤-2
