The carbon dioxide carried in the blood is actually combined with water and carried in the red blood cells in the form of carbonic acid, which has a dissociation constant:
H₂CO₃ ↔ H⁺ + CO₃⁻
When the pH of the blood decereases, the concentration of H⁺ ions in the blood becomes high. This causes the equilibrium to shift backwards, as per Le Chatelier's principle. The H⁺ ions are converted back to carbonic acid and the pH is increased. The opposite occurs when the pH is too high.
Answer:
The electromagnetic spectrum is a range of electromagnetic waves, in order of increasing wavelength/decreasing frequency
The answer is mitochondria.
About 4 times more ATP is generated during oxidative phosphorylation than substrate-level phosphorylation.
<h3>Oxidative phosphorylation:</h3>
In the metabolism process known as oxidative phosphorylation, also known as electron transport-linked phosphorylation or terminal oxidation, cells employ catalysts to oxidize carbohydrates, liberating chemical energy and producing adenosine triphosphate (ATP) as a consequence.
- According to some modern studies, the ATP output after aerobic respiration is only approximately 30-32 ATP molecules /molecule of glucose, rather than 36-38, because:
During oxidative phosphorylation,
- the ATP: NADH+H+ and ATP: FADH2 ratios appear to be 2.5 and 1.5 instead of 3 and 2, respectively.
<h3>Substrate level phosphorylation:</h3>
- Substrate-level phosphorylation is a metabolic activity that produces ATP or GTP by the direct transfer of a phosphoryl (PO3) group from another phosphorylated chemical to ADP or GDP.
- Substrate level phosphorylation happens via glycolysis and the Krebs cycle. It happens in two phases during glycolysis, and because 2 molecules are involved, it eventually creates 4 ATP from a glucose molecule.
- As a result, the total ATP molecules generated from substrate-level phosphorylation of a glucose molecule during aerobic respiration will be 4+2 = 6.
Therefore, it is concluded that ATP generated during oxidative phosphorylation is 30-6=24 or 32-6=26 i.e., about 4 times than substrate-level phosphorylation.
Learn more about substrate level phosphorylation here:
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There are four haploid nuclei present in the last stage of meiosis II, which is telophase II. That is because the cytoplasm was being divided that results into four nuclei. Each of these has 23 chromosomes that contain a chromatid.
