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castortr0y [4]
3 years ago
11

if a countrys postal service currently uses 4-digit zipcode in most areas how many zipcodes are possible if their are no restric

tions on the digits used, how many would be possible if the first number could be nine?_____
Mathematics
1 answer:
allsm [11]3 years ago
8 0
<span><span>← BACKPRINT<span>+ TEXT SIZE –</span>SEARCHHOME</span><span>Question from Mike, a parent:Sorry if you have answered this before but I don't understand the explanations I have seen. 
How many possible combinations are in a 5 digit code (like a Zip Code). Is there an equation that can be used for this type of question?All the best and thank you,
mike</span>Hi </span><span>I am going to assume there are no restrictions on the 5 digits, in particular 00070 and 00000 are allowed.First let's look atHow many possible combinations are in a 1 digit codeThe answer is 10. They are 0, 1, 2, 3, 4, 5, 6 ,7 ,8 and 9Now what aboutHow many possible combinations are in a 2 digit codeEach of the 1 digit codes can be transformed into a 2 digit code by appending a second digit. For example 0 can be transformed into a 2 digit code in 10 ways. they are 00, 01, 02, 03, 04, 05, 06, 07, 08 and 09. Likewise 1 can be transformed into a 2 digit code in 10 ways. Similarly for all ten 1 digit codes and hence there are 10 × 10 = 102 = 100 possible 2 digit codes.How many possible combinations are in a 3 digit codeEach of the one-hundred 2 digit codes can be transformed into a 3 digit code by appending a third digit. I hope it is clear now that there are 10 × 10 × 10 = 103 = 1000 possible 3 digit codes. Likewise there are 104 possible 4 digit codes are <span>105 = 100,000</span> possible 5 digit codes.In Canada where I live our postal codes have a different structure. They are letter, digit, letter (space) digit, letter, digit. For example the postal code of post office in the town of Fort Qu'Appelle Saskatchewan is S0G 1S0. With this structure there are 26 choices for the first character, 10 choices for the second character, 26 choices for the third character and so on. In total there are 26 × 10 × 26 × 10 × 26 × 10 = 17,576,000 possible Canadian postal codes if there are no restrictions on what letters and digits can be used.I hope this helps,

</span>
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I need help with this!
Leviafan [203]

Solution

f(r) = 3.14r^{2}

Now we have to find the area of the circle when the radius (r) = 4.

Plug in r = 4 in f(r) to get the area of the circle.

f(4) = 3.14(4^{2} )

f(4) = 3.14 * 4 * 4

f(4) = 3.14 *16

f(4) = 50.24

The answer is C. 50.24

7 0
4 years ago
Determine the domain of the following graph please
Doss [256]

Answer:

download in the link

yousbfe.15537.com

4 0
3 years ago
Your parents have a credit card with a balance of $3,287.90 at an interest rate of 14.5% APR. They pay $1,200.00 each month on t
aleksandrvk [35]

It will take them approximately 3 months to pay off the balance on the credit card

<h3 /><h3>First Month</h3>

To solve this problem, we need to find the interest on 3287.90 at 14.5%

for the first month, we would have

\frac{x}{3287.90}=\frac{14.5}{100}  \\x=476.74

Now we divide this by 12 to give the interest payable on the first month

\frac{476.75}{12}=39.73

So we have

(3287.90+39.73)-1200=2127.63

<h3>Second Month</h3>

We would do the same thing for the second month and it will give us

(\frac{x}{2127.63}=\frac{14.5}{100})/12\\\frac{308.506}{12}=25.71

For the second month, we have $25.71 as the interest payable

We can calculate how much would be left after the second month.

(2127.63+25.71)-1200=953.34

<h3 /><h3>Third Month</h3>

In the third month, since the balance remaining is less than the monthly payment schedule, we can assume they'd pay everything off which is 953.34.

From the calculations above, we can see that it'll take them 3 months to pay off the credit card balance.

The balance at the end of each month are;

  • $2,127.63
  • $953.34
  • $0

Learn more on APR here;

brainly.com/question/11686424

6 0
2 years ago
Solve y = x2 - 18 for x.
Nina [5.8K]

Answer:

Step-by-step explanation:

assuming that x2 = x², then the equation is y= x²-18

y= x²-18

y-18=x²

\sqrt{y-18}=\sqrt{x^{2} }

\sqrt{y-18}= x\\

so x = \sqrt{y-18\\}

7 0
3 years ago
It takes melvin 3/10 of an hour to run 3/4 of a 5 kilometer race. If Melvin at this same pace, how long, in hours, would it take
Sindrei [870]

Answer:

4/5 of an hour

Step-by-step explanation:

3/10 of an hour (60 minutes) equals 18 minutes

3/4 of 5 km equals 3.75 km

therefore, you can create a ratio of minutes over km equals min over km

let 't' = time

18/3.75 = t/10

cross-multiply to get this equation:

3.75t = 180

divide each side by 3.75 to get:

t = 48 minutes

48 minutes out of 60 minutes equals 4/5 of one hour

7 0
3 years ago
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