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Natali [406]
3 years ago
13

A quiz consists of 50 multiple choice questions, each with five possible answers, only one of which is correct. Find the mean an

d the standard deviation of the number of correct answers
Mathematics
1 answer:
Irina-Kira [14]3 years ago
4 0

Answer:

\mu=10\\\\\sigma=2.828

Step-by-step explanation:

-This is a binomial probability  function.

-Given that the probability of success is p=0.2 and the sample size, n=50.

-The  mean is calculated using the formula:

\mu=np\\\\=50\times 0.2\\\\=10

-We then calculate the standard deviation as:

\sigma=\sqrt{npq}, \ \ q=1-p\\\\=\sqrt{50\times 0.2(1-0.2)}\\\\=2.828

Hence, the mean is 10 ad the standard deviation is 2.828

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Find valuable asked for witch ABCD must be a parallelogram, <br> 1<br> 11<br> 2<br> 15
riadik2000 [5.3K]

4x+7 = x+10   parallel sides have to be equal in a parallelogram

subtract x

3x +7 = 10

subtract 7 from each side

3x =3

divide by 3

x =1


4 0
3 years ago
80% of the six graders at Harrison middle school Are going on a field trip to the museum there a total of 685 students in six gr
irga5000 [103]
80% converted to a decimal is 80/100=0.8

Multiply the total with the percent 685*0.80

The answer is 540
8 0
3 years ago
. Imagine a game of 3 players where exactly one player wins in the end and all players have equal chances of being the winner. T
lbvjy [14]

Answer:

5/9

Step-by-step explanation:

Number of players = 3

number of times game is repeated = 4

P( any person wins a game ) = 1/3

P ( any person does not win a game ) = 1 - 1/3 = 2/3

P ( any person wins no game in 4 attempts ) = ( 2/3 )^4 = 16/81

<em>Note : each player has equal chance of winning </em>

<u>Find the probability that there is at least one person who wins no games </u>

lets represent the probability of each player not wining a game with alphabet A

A1 = player 1 wins no game

A2 = player 2 wins no game

A3 = players 3 wins no game

Applying the inclusion-exclusion formula

<em>P( A1 ∪ A2 U A3 )</em><em> = P(A1 ) + P(A2) + P(A3) - P( A1 ∩ A2 ) - P( A2 ∩ A3 ) - P( A1            ∩ A3 )  + P( A1 ∩ A2 ∩ A3 ) </em>

where

P( A1 ∩ A2 ) = P( A1 wins all games )

P ( A1 wins all games in 4 attempts ) = ( 1/3 )^4 = 1/81

P( A1 ∩ A2 ∩ A3 ) = P ( no players wins any game in 4 attempts ) = 0

Hence

P( A1 ∪ A2 U A3 ) = 16/81 + 16/81 + 16/81 - 1/81 - 1/81 - 1/81 - 0 = 5/9

6 0
3 years ago
Help please I don’t know the answer ????
pentagon [3]

To find the answer to a problem like this, we need to look for patterns in the number!

It looks likes x = 2y

Or in other words, (y is being multiplied by 2 to find x!)

**Now that we've discovered this pattern, we can confidently say that ...

<u>the number</u><u> 6</u><u> belongs in</u><u> #1 </u>

5 0
3 years ago
If I have an equation in which x = pounds, and y = total cost, can I substitute quarts into the equation
Colt1911 [192]

Answer:

Yes, you can

Step-by-step explanation:

As a point of reference, assume the equation is:

y = 5x

Where

y = total\ cost

and

x = pounds

In standard unit of conversion:

1\ pound = 0.4793\ quart

So:

x\ pounds = 0.4793x\ quart

Substitute 0.4793x for x in y = 5x

y = 5 * 0.4793x

y = 2.3965x

The above equation is the equivalent of y = 5x in quarts

<em>So, irrespective of what the equation is, you can always substitute quarts into the equation.</em>

8 0
3 years ago
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