Write an equation is slope-intercept form for the line parallel to y=7x+9 that passes through (4,10)

1 answer:

7 0

Since they are parallel, the co-efficient of x will be the same. So m=7.
Y=Mx+c. So if we substitute the values with the coordinates, we get 10= (7*4) +c . Therefore c= -18.
So the final answer is:

Y=7x - 18

AND ALSO PLEASE MARK ME BRAINLIEST. THANK YOU SO MUCH

You might be interested in

Given the expotential function f(x) = 4(3)^x find f(0) and f(1)

RoseWind [281]

Answer:

4 and 12

Step-by-step explanation:

Given

f(x) = 4 $(3)^{x}$ , then

f(0) = 4 $(3)^{0}$ = 4 × 1 = 4 [ $a^{0}$ = 1 ]

f(1) = 4 $(3)^{1}$ = 4 × 3 = 12

5 0

2 years ago

A line passes through the point (-6,-9) and has a slope of 5/2.

mezya [45]

$(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-9})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{5}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-9)}=\stackrel{m}{\cfrac{5}{2}}(x-\stackrel{x_1}{(-6)})\implies y+9=\cfrac{5}{2}(x+6) \\\\\\ y+9=\cfrac{5}{2}x+15\implies y=\cfrac{5}{2}x+6$