Answer:
(12, 40)
Step-by-step explanation:
The first thing is to assume that we have a point with the following coordinates (x, y).
Now, we can have two different cases since the meaning of the expansion of a point is moving to a new point that is a greater distance from the origin if we are expanding by a value, that is, an integer in the system of coordinates and the other case is that if we are dilating by a fraction that is between 0 <x <1, then the distance from the origin decreases.
Now, the point (x, y) goes through an expansion by a scale factor f (with the origin as the expansion point), then the new coordinate of the point = [f * x, f * y], that scale factor has the value of 3, so if we replace we have:
(3 * 4, 4 * 10) = (12, 40)
X^2+8x+15
= x^2 + 5x + 3x + 15
= x(x+5) + 3(x+5)
= (x+5)(x+3)
Answer:
Step-by-step explanation:
- Option A
![[x+5=20]](https://tex.z-dn.net/?f=%5Bx%2B5%3D20%5D)
tells us that: When we add 5 to a variable x, we get 20. As it has a unique value for x and is completely equal to it(i.e. 15), It is an equality.
- Option B
![[x=5]](https://tex.z-dn.net/?f=%5Bx%3D5%5D)
tells us that: A variable x equals to 5. Hence, as x is unique for 5 and is wholly equal to it, it's an equality too. - Option C
tells us that: A variable x isn't 5 but lesser than it. As we cannot equate it to 5, nor we are given the nature of the variable x, it is an Inequality. - Option D
![[x+5]](https://tex.z-dn.net/?f=%5Bx%2B5%5D)
is an expression; It can't be called an equation or an inequality unless we relate it with another expression.
The answer is C
you substitute 3200 in for y
3200 = 168x +8
3192 = 168x
x=19
2n + n/2 = 10
4n/2 +n/2 =10
5n/2 = 10
5n = 20
n = 4
