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2 years ago

What is the equation of the line? y=3x Y=1/3x Y=1/3x+2 Y=3x+2

Mathematics

2 answers:

Mrrafil [7]2 years ago

6 0

Answer:

Y = 1/3x + 2

Step-by-step explanation:

Since the line increases by 1 unit then goes to right 3 units the line equation must have a slope of 1/3 and must have a y intercept of + 2 since the line crosses the Y axis at +2

kotykmax [81]2 years ago

4 0

Answer: y=1/3x+2 is the correct answer just took the test

Step-by-step explanation:

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40 POINTS <br><br> please answer me this question with an explanation

user100 [1]

Answer:

(16/3,-4)

Step-by-step explanation:

y=-3/4x & y=3/2x -12
then solve for x which means -3/4x=3/2x-12
then the value of x=16/3
put the x value in one equation
y=3/4(16/3)
then the value of y=-4

4 0

1 year ago

Read 2 more answers

I need help on this question

Morgarella [4.7K]

Answers : A and D

Step - by - step explanation :

tip : when finding constant of proportionality it's always Y divided by X

A = what is 22.5 divided by 3 ? 7.5 ( now multiply 7.5 by the next X [ 4 ] )

what is 7.5 x 4 ? 30 ( and since on the graph it also says 30 then you can assume this one has a proportional relationship )

B = what is 12 divided by 3 ? 4 ( now multiply 4 by the next X [ 5 ] )

what is 4 x 5 ? 20 ( and because the graph says 25 then you know it's NOT a proportional relationship )

C = what is 8.5 divided by 2 ? 4.25 ( now multiply 4.25 by the next X [ 5 ] )

what is 4.25 x 5 ? 21.25 ( and because the graph says 22.5 then you know it's NOT a proportional relationship )

D = what is 10 divided by 2 ? 5 ( now multiply 5 by the next X [ 3 ] )

what is 5 x 3 ? 15 ( and since on the graph it also says 15 then you can assume this one has a proportional relationship )

( sorry it took me so long to write this )

6 0

2 years ago

Please help!! x = 2 - 3 cos t, y = 1 + 4 sin t in rectangular form?<br><br> thank you! :)

sukhopar [10]

Answer:

$\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1$

Step-by-step explanation:

$x=2-3\cos(t)$

$y=1+4\sin(t)$

Let's solve for $\cos(t)$ in the first equation and then solve for $\sin(t)$ in the second equation.

I will then use the following identity to get right of the parameter, $t$ :

$\cos^2(t)+\sin^2(t)=1$ (Pythagorean Identity).

Let's begin with $x=2-3\cos(t)$ .

Subtract 2 on both sides:

$x-2=-3\cos(t)$

Divide both sides by -3:

$\frac{x-2}{-3}=\cos(t)$

Now time for the second equation, $y=1+4\sin(t)$ .

Subtract 1 on both sides:

$y-1=4\sin(t)$

Divide both sides by 4:

$\frac{y-1}{4}=\sin(t)$

Now let's plug it into our Pythagorean Identity:

$\cos^2(t)+\sin^2(t)=1$

$\frac{x-2}{-3})^2+(\frac{y-1}{4})^2=1$

$\frac{(x-2)^2}{(-3)^2}+\frac{(y-1)^2}{4^2}=1$

$\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1$

5 0

2 years ago

Read 2 more answers

Help fast plz I WILL DO ANYTHING

kaheart [24]

Answer:

I only have 2

Step-by-step explanation:

each sides is multiplying by 2

each order is multiplying by 12

5 0

2 years ago

3) Divide x3 + 4x2 – 3x – 12 by (x + 4)

alex41 [277]

Answer:

Factor the numerator and denominator and cancel out the common factors.

x ^2 − 3 is your final answer.

Step-by-step explanation:

Hope that this helps you out! :)

If you have any questions please put them in the comment section below this answer.

Have a great rest of your day/night!

Please thank me on my profile if this answer has helped you.

7 0

2 years ago