Please help me. I have been stuck on this question. I can't seem to figure it out.

Yello Bus Lines uses the units-of-activity method in depreciating its buses. One bus was purchased on January 1, 2019, at a cost

worty [1.4K]

A is the best choice good luck

4 0

3 years ago

Simpkin Corporation owns manufacturing facilities in States A, B, and C. B uses a three- factor apportionment formula under whic

ivanzaharov [21]

Answer:

Simpkin Corporation

Simpkin's apportionable income assigned to B is:________.

b. $533,333

Explanation:

a) Data and Calculations:

Apportionable operating income = $1,000,000

State A State B State C Totals

Sales $400,000 $800,000 $300,000 $1,500,000

Payroll 100,000 150,000 50,000 300,000

Property 200,000 200,000 200,000 600,000

State B's portion of the operating income = $1,000,000 * $800,000/$1,500

= $533,333

5 0

3 years ago

The Cole Beverage Company (CBC) has a soft drink product that has a constant annual demand of 3,600 cases per year. A case of th

skad [1K]

Answer:

a. 480

Explanation:

The computation of the economic order quantity is given below:

$EOQ = \sqrt{\frac{2\times annual \ demand \times ordering\ cost }{carrying \ cost}} \\\\= \sqrt{\frac{2\times 3600\times \$32}{\$1} }$

= 480 units

The carrying cost could be determined below:

= $4 × 25%

= $1

hence, the carrying cost is $1

Therefore the economic order quantity is 480

Thus, the correct option is a.

7 0

2 years ago

"why would a producer decide to produce in a competitive market in which she will earn zero profit in the long run?"

notka56 [123]

<span>Money is not the only measure of success and not everything is transactional. A producer may choose to produce for many reasons. Among them, working with exceptional talent as well as gaining experience and getting street creds.</span>

3 0

3 years ago

Read 2 more answers

The incomes of all families in a particular suburb can be represented by a continuous random variable. It is known that the medi

liberstina [14]

Answer:

a) 0.10 or 10%

b) 0.5417 or 54.17%

Explanation:

a) The median income of $60,000 is at the 50th percentile of the distribution. If 40% if incomes are above $72,000, then an income of $72,000 is at the 60th percentile of the distribution. Therefore, the probability that a family's income will be between $60,000 and $72,000 is:

$P( \$60,000 \leq X \leq \$72,000)=0.6-0.5\\P( \$60,000 \leq X \leq \$72,000)=0.1 = 10\%$

b) If the distribution is known to be uniform, the probability that a random chosen family has an income below $65,000 is:

$P( X \leq \$65,000)=0.5+\frac{65,000-60,000}{72,000-60,000}*0.1\\ P( X \leq \$65,000)=0.5417 =54.17\%$

7 0

3 years ago