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harina [27]
3 years ago
7

Help please easy for 5 grade or any grade plsss help⭐️

Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0
It is G
jgxufxyldzlhfxuxutcutx
Rasek [7]3 years ago
4 0

Answer:

It is G

Step-by-step explanation:

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I was sick for a week and never got tought this stuff can you help
Crank

1. We know that Sum of Three Angles in a Triangle is 180

⇒ m∠1 + 75 + 40 = 180

Option B is the Answer

2. We know that Sum of Three Angles in a Triangle is 180

⇒ ∠1 + 30 + 20 = 180

⇒ ∠1 + 50 = 180

⇒ ∠1 = 180 - 50

⇒∠1 = 130

3. We know that Sum of Three Angles in a Triangle is 180

⇒ ∠1 + 75 + 35 = 180

⇒ ∠1 + 110 = 180

⇒ ∠1 = 180 - 110

⇒ ∠1 = 70

4. We know that Sum of Three Angles in a Triangle is 180

⇒ ∠1 + 60 + 60 = 180

⇒ ∠1 + 120 = 180

⇒ ∠1 = 180 - 120

⇒ ∠1 = 60

5. We know that Sum of Three Angles in a Triangle is 180

We can notice that the Given Triangle is a Right Angled Triangle

We know that One Angle in Right Angled Triangle is 90

⇒ ∠2 + 90 + 30 = 180

⇒ ∠2 + 120 = 180

⇒ ∠2 = 180 - 120

⇒ ∠2 = 60

6. We know that Sum of Three Angles in a Triangle is 180

We can notice that the Given Triangle is a Right Angled Triangle

We know that One Angle in Right Angled Triangle is 90

⇒ ∠2 + 90 + 40 = 180

⇒ ∠2 + 130 = 180

⇒ ∠2 = 180 - 130

⇒ ∠2 = 50

7. We know that Sum of Three Angles in a Triangle is 180

We can notice that the Given Triangle is a Right Angled Triangle

We know that One Angle in Right Angled Triangle is 90

⇒ ∠2 + 90 + 45 = 180

⇒ ∠2 + 135 = 180

⇒ ∠2 = 180 - 135

⇒ ∠2 = 45

8. We know that the Exterior Angle of one Vertex of a Triangle is the Sum of Other two vertices interior angles.

⇒ ∠3 = 80 + 60

⇒ ∠3 = 140

9. We know that the Exterior Angle of one Vertex of a Triangle is the Sum of Other two vertices interior angles.

⇒ ∠3 = 40 + 35

⇒ ∠3 = 75

10. We know that the Exterior Angle of one Vertex of a Triangle is the Sum of Other two vertices interior angles.

⇒ ∠3 = 75 + 65

⇒ ∠3 = 140

11. We know that Sum of Three Angles in a Triangle is 180

⇒ x + x + 108 = 180

⇒ 2x + 108 = 180

⇒ 2x = 180 - 108

⇒ 2x = 72

⇒ x = 36

12. We know that Sum of Three Angles in a Triangle is 180

⇒ 60 + 60 + 3x = 180

⇒ 3x + 120 = 180

⇒ 3x = 180 - 120

⇒ 3x = 60

⇒ x = 20

13. We know that Sum of Three Angles in a Triangle is 180

We can notice that the Given Triangle is a Right Angled Triangle

We know that One Angle in Right Angled Triangle is 90

⇒ (5x + 3) + 47 + 90 = 180

⇒ 5x + 140 = 180

⇒ 5x = 180 - 140

⇒ 5x = 40

⇒ x = 8

14. We can notice that the Given Diagram is a Right angled Triangle :

⇒ ∠1 + 90 + 45 = 180

⇒ ∠1 + 135 = 180

⇒ ∠1 = 180 - 135

⇒ ∠1 = 45

8 0
3 years ago
Simplify the expression √6 (√33=7)
marin [14]
14.07 is the answer to the question above
7 0
3 years ago
if f(1) = -5 and f(n) = f(n-1) +7, find the first four terms and the common difference of the sequence
Alex_Xolod [135]

Answer:

- 5, 2, 9, 16 and d = + 7

Step-by-step explanation:

to obtain the first four terms substitute n = 2, 3, 4 into the recursive formula

f(1) = - 5 ← given

f(2) = f(1) + 7 = - 5 + 7 = 2

f(3) = f(2) + 7 = 2 + 7 = 9

f(4) = f(3) + 7 = 9 + 7 = 16

common difference d = 16 - 9 = 9 - 2 = 2 - (- 5) = 7



6 0
3 years ago
Which section of the function is decreasing? (4 points)
vredina [299]

Answer:

Step-by-step explanation:

D

8 0
3 years ago
Read 2 more answers
The heat developed in an electric wire varies jointly as the wires resistance, the time the current flows, & the square of t
never [62]

Answer:

4 ohms

Step-by-step explanation:

The question is "In two minutes a current of 5 amps develops 1,200 heat units in a wire of 8 ohms resistance. What resistance does a similar wire have, which develops 6,000 heat units with a current of 10 amps in 5 minutes?"

Current, I₁ = 5 A

Heat, Q₁ = 1200 units

Resistance, R₁ = 8 ohms

Time, t₁ = 2 min = 120 s

New heat, Q₂ = 6000 units

Current, I₂ = 10 A

New time, t₂ = 5 min = 300 s

We need to find the new resistance.

Heat developed is given by :

Q=I^2Rt

\dfrac{Q_1}{I_1^2R_1t_1}=\dfrac{Q_2}{I_2^2R_2t_2}\\\\R_2=\dfrac{Q_2\times I_1^2R_1t_1}{Q_1I_2^2t_2}\\\\R_2=\dfrac{6000\times 5^2\times 8\times 120}{1200\times 10^2\times 300}\\\\=4\ \Omega

So, the new resistance is 4 ohms.

5 0
3 years ago
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