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harina [27]
3 years ago
7

Help please easy for 5 grade or any grade plsss help⭐️

Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0
It is G
jgxufxyldzlhfxuxutcutx
Rasek [7]3 years ago
4 0

Answer:

It is G

Step-by-step explanation:

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An architect is constructing a model building by using a ratio os 1:300. If the height of the scale model is 3 1/2 inches what i
atroni [7]
\bf \cfrac{model}{actual}\qquad 1:300\qquad \cfrac{1}{300}\qquad \qquad \cfrac{3\frac{1}{2}}{a}=\cfrac{1}{300}\implies \cfrac{\frac{3\cdot 2+1}{2}}{a}=\cfrac{1}{300}
\\\\\\
\cfrac{\quad \frac{7}{2}\quad }{a}=\cfrac{1}{300}\implies \cfrac{\quad \frac{7}{2}\cdot 300\quad }{1}=a\implies 1050=a
7 0
3 years ago
The height of a cone is two times its base diameter. What is the volume of the cone in terms of its base radius r? V = r2 V = r3
Gnom [1K]
So hmm check the picture below

the radius "r" is half the diameter, meaning, the diameter is 2r long
now, if the height "h" is twice "d" or 2d, then that means h = 2(2r)

thus    \bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\qquad 
\begin{cases}
h=height\\
r=radius\\
------\\
h=2(2r)
\end{cases}\implies V=\cfrac{\pi r^2[2(2r)]}{3}
\\\\\\
V=\cfrac{4\pi r^3}{3}

8 0
3 years ago
The breaking strengths of cables produced by a certain manufacturer have a mean, u, of 1750 pounds, and a standard deviation of
AlladinOne [14]

Answer:

We accept the null hypothesis that the  breaking strength mean is less and equal to 1750 pounds and has not increased.

Step-by-step explanation:

The null and alternative hypotheses are stated as

H0:  u ≥ 1750   i.e the mean is less and equal to 1750

against the claim

Ha: u > 1750  ( one tailed test)  the mean is greater than 1750

Sample mean = x`= 1754

Population mean = u = 1750

Population deviation= σ = 65 pounds

Sample size= n = 100

Applying the Z test

z= x`- u / σ/ √n

z= 1754- 1750 / 65/ √100

z= 4/6.5

z= 0.6154

The significance level alpha = 0.1

The z - value at 0.1 for one tailed test is ± 1.28

The critical value is z > z∝.

so

0.6154 is < 1.28

We accept the null hypothesis that the  breaking strength mean is less and equal to 1750 pounds and has not increased.

8 0
3 years ago
A triangle has side lengths of (8.1t-6.1)(8.1t−6.1) centimeters, (8.1t+7.1)(8.1t+7.1) centimeters, and (3.4u+1.9)(3.4u+1.9) cent
Mila [183]

Answer:

<em>(16.2t+3.4u+2.9)cm</em>

Step-by-step explanation:

A triangle is a plane shape that has three sides. <em>The perimeter of a triangle is gotten by taking the sum of all the lengths of the three sides</em>. Let the length of the three sides by s1, s2 and s3, the perimeter of the triangle will be expressed as;

P = s1+s2+s3

Given the side lengths

s1 = (8.1t-6.1)cm

s2 = (8.1t+7.1)cm

s3 = (3.4u+1.9)cm

Perimeter of the triangle = 8.1t-6.1+8.1t+7.1+3.4u+1.9

collect the like terms

P = 8.1t+8.1t+3.4u-6.1+7.1+1.9

P = 16.2t+3.4u+2.9

<em>Hence the expression that represents the perimeter, in centimeters, of the triangle is  (16.2t+3.4u+2.9)cm</em>

5 0
3 years ago
Find all values of k so that the following system has no solutions x²+(y-k)²=36 ; y=5x+k.Illustrate with a graph.
musickatia [10]

Step-by-step explanation:

x^2+(y-k)^2=36

y=5x+k

Substituting y in the first equation

x^2+(5x+k-k)^2=36\\\Rightarrow x^2+25x^2=36\\\Rightarrow 26x^2=36\\\Rightarrow x^2=\frac{36}{26}\\\Rightarrow x=\sqrt{\frac{36}{26}}\\\Rightarrow x=\pm 1.17

At x = 1.17

y=5\times 1.17+k\\\Rightarrow y=5.85+k

At x = -1.17

y=5\times -1.17+k\\\Rightarrow y=-5.85+k

The intersection points are (1.17, 5.85k) and (-1.17, -5.85k)

The graph would intersect regardless of what value k is.

5 0
3 years ago
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