H(t) = −16t^2 + 75t + 25
g(t) = 5 + 5.2t
A)
At 2, h(t) = 111, g(t) = 15.4
At 3, h(t) = 106, g(t) = 20.6
At 4, h(t) = 69, g(t) = 25.8
At 5, h(t) = 0, g(t) = 31
The heights of both functions would have been the closest value to each other after 4 seconds, but before 5 seconds. This is when g(x) is near 30 (26-31), and the only interval that h(t) could be near 30 is between 4 and 5 seconds (as it is decreasing from 69-0).
B) The solution to the two functions is between 4 and 5 seconds, as that is when their height is the same for both g(t) and h(t). Actually the height is at 4.63 seconds, their heights are both
What this actually means is that this time and height is when the balls could collide; or they would have hit each other, given the same 3-dimensional (z-axis) coordinate in reality.
Answer:
height: 125m; distance: 500m
Step-by-step explanation:
x = 250
f(x) = x − 0.002x2
f(x) = 250 − 0.002(250 )2
= 250 − 0.002(62,500)
= 250 − 125
= 125
250 times 2 = 500
Answer:g(x) is more narrow than x^2
Step-by-step explanation:the bigger the coefficient in front othe x^2 the skinny or narrow the parabola becomes our teacher would say x^2 is the parent function runs 1 mile you are 3x^2 your in 3 miles whose skinner lol
It's C because the equations are similar
Answer:
Slope = -5/8
Step-by-step explanation:
Take 2 points from the graph where the line is. Point 1: (1 , 6). Point 2: (9 , 1).
We are going to use the formula for finding the slope of a line now.
y2 - y1/x2 - x1 = 1 - 6/9 - 1 = -5/8
Slope = -5/8
