Find the area of the parallelogram with vertices A(−1,2,3), B(0,4,6), C(1,1,2), and D(2,3,5).
cupoosta [38]
Answer:
5*sqrt3
Step-by-step explanation:
The vector AB= (0-(-1), 4-2,6-3) AB= (1,2,3)
The modul of AB is sqrt(1^2+2^2+3^2)= sqrt14
The vector AC is (1-(-1), 1-2, 2-3)= (2,-1,-1)
The modul of B is sqrt (2^2+(-1)^2+(-1)^2)= sqrt6
AB*AC= modul AB*modul AC*cosA
cosA=( 1*2+2*(-1)+3*(-1))/ sqrt14*sqrt6= -3/sqrt84=
sinB= sqrt (1- (-3/sqrt84)^2)= sqrt75/84= sqrt 25/28= 5/sqrt28
s= modul AB*modul AC*sinA= sqrt14*sqrt6* 5/ sqrt28= 5*sqrt3
Answer:
(5x - 3y)(25x² +15xy + 9y²)
Step-by-step explanation:
125x³ - 27y³ is a difference of cubes and factors in general as
a³ - b³ = (a - b)(a² + ab + b²)
Given
125x³ - 27y³
= (5x)³ - (3y)³
= (5x - 3y)((5x)² + (5x)(3y) + (3y)²)
= (5x - 3y)(25x² + 15xy + 9y²)
Answer:
11.27cm
Step-by-step explanation:
705% of 14milimeters
705/100 X 14 = 98.7
increase by adding 98.7milimeter to 14milimeter
98.7+14= 112.7milimeter or 11.27cm
Answer:
the answer is 47 sprinklers
Step-by-step explanation:
so the system is 188 and there is one sprinkler every 4 feet
so 188/4 which would give u 47
