It would be A. You can find this out by using SOH CAH TOA,
SOH means sin= opposite/hypotenuse
CAH mean cos= adjacent/hypotenuse
TOA means tangent= opposite/adjacent
You would use CAH since you are trying to find cos∠C
You would have cos∠C=10/26.
26 is the hypotenuse since it is opposite the right angle and is the biggest side.
10 is the adjacent since it is right next to C
You would simplify this down to 5/13 by dividing by 2.
This gives you A.
The shaded area in the image is 86.1 square inches.
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How to get the shaded area?</h3>
Remember that for a circle of diameter D, the area is given by:
A = pi*(D/2)²
Where pi = 3.14, and here we have half-circles, so we need to add a factor 0.5
The area of the shaded figure, the area of the shaded figure will be the area of the half circle with diameter of 17in minus the area of the half circle with a diameter of 8.5 in, so the area is:
area = 0.5*3.14*(17in/2)² - 0.5*3.14*(8.5in/2)² = 86.1 in²
Learn more about area:
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Part A:
Consider from x = -5 to x = -4, they are 1 unit apart and the difference of their outputs is given by:
-3 - (-11) = -3 + 11 = 8.
Thus, the value of the output increases by 8 units for each one unit increase in the input.
Part B:
Consider from x = -3 to x = -1, they are 2 units apart and the difference of their outputs is given by:
21 - 5 = 16.
Thus, the value of the output increases by 16 units for each two units increase in the input.
Part C:
Consider from x = 0 to x = 3, they are 3 units apart and the difference of their outputs is given by:
53 - 29 = 24.
Thus, the value of the output increases by 24 units for each three units increase in the input.
Part D:
It can be noticed that the ratio difference in the outputs to the input intervals are equal for all the given input intervals.
i.e 8 / 1 = 16 / 2 = 24 / 3.
Answer:
This is an exponential function
Step-by-step explanation:
f(x)=2(3)^x is one example of the exponential function. Since f(0) = 2(1) = 2, the y-intercept is (0, 2). The x-axis is the horizontal asymptote. The graph begins in Quadrant II, passes through (0, 2) and continues to increase, faster and faster, in Quadrant I. Next time, please be more specific about what you'd like to know.
Add 2.38 and 4.89 then subtract 3 giving you 4.27