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RSB [31]
3 years ago
13

i don't know if this makes sense but I have to make 8X to the 12 power a number in parentheses. I have to fill in the boxes with

a different number​

Mathematics
1 answer:
Scilla [17]3 years ago
8 0

\bf 8x^{12}\qquad \begin{cases} 8=&2\cdot 2\cdot 2\\ &2^3\\ x^{12}=&x^{4\cdot 3}\\ &(x^4)^3 \end{cases}\implies 2^3(x^4)^3\implies \left( 2x^4 \right)^3

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Is my answer correct? // tell me if i'm wrong with details!!
Anna11 [10]

Answer:

B.

Step-by-step explanation:

This is vertical reflection, because reflections are made across vertical lines.

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3 years ago
Which shows the expressions in the order they would appear on a number line from least to greatest?
Illusion [34]
<span>c.)11 over 9, square root of 5, square root of 11, square root of 20, 2 to the power of 3

In order to compare, try to bring all of them into one similar form, like decimal.
Then, 11/9 = 1.22
Then, we can compare numbers under root, as 5 would be smaller than 11 which in turn is smaller than the 20, then 2^3 is 8, largest in series.

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3 years ago
Read 2 more answers
,please help me solve these 2. problems I am having trouble
Harlamova29_29 [7]
Hi,

1) D

Working :
If the bell rings for 2 weeks straight that means it rings for 14 days.

The bell rings 48 times a day (2 * 24).

The answer is then: 48*14 = 672

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4 0
3 years ago
This is a 3 part 1 question each part on how to locate the plane and a small explanation report working out the recovery details
sesenic [268]

Third leg.

The crew flies at a speed of 560 mi/h in direction N-20°-E.

The wind has a speed of 35 mi/h and a direction S-10°-E.

We then can draw this as:

We have to add the two vectors to find the actual speed and direction.

We will start by adding the x-coordinate (W-E axis):

\begin{gathered} x=560\cdot\sin (20\degree)+35\cdot\sin (10\degree) \\ x\approx560\cdot0.342+35\cdot0.174 \\ x\approx191.53+6.08 \\ x\approx197.61 \end{gathered}

and the y-coordinate (S-N axis) is:

\begin{gathered} y=560\cdot\cos (20\degree)-35\cdot\cos (10\degree) \\ y\approx560\cdot0.940-35\cdot0.985 \\ y\approx526.23-34.47 \\ y\approx491.76 \end{gathered}

Then, the actual speed vector is v3=(197.61, 491.76).

The starting location for the third leg is R2=(216.66, 167.67) [taken from the previous answer].

Then, we have to calculate the displacement in 20 minutes using the actual speed vector.

We can calculate the movement in each of the axis. For the x-axis:

\begin{gathered} R_{3x}=R_{2x}+v_{3x}\cdot t \\ R_{3x}=216.66+197.61\cdot\frac{1}{3} \\ R_{3x}=216.66+65.87 \\ R_{3x}=282.53 \end{gathered}

NOTE: 20 minutes represents 1/3 of an hour.

We can do the same with the y-coordinate:

\begin{gathered} R_{3y}=R_{2y}+v_{3y}\cdot t \\ R_{3y}=167.67+491.76\cdot\frac{1}{3} \\ R_{3y}=167.67+163.92 \\ R_{3y}=331.59 \end{gathered}

The final position is R3 = (282.53, 331.59).

To find the distance from the origin and direction, we transform the cartesian coordinates of R3 into polar coordinates:

The distance can be calculated as if it was a right triangle:

\begin{gathered} d^2=x^2+y^2_{} \\ d^2=282.53^2+331.59^2 \\ d^2=79823.20+109951.93 \\ d^2=189775.13 \\ d=\sqrt[]{189775.13} \\ d\approx435.63 \end{gathered}

The angle, from E to N, can be calculated as:

\begin{gathered} \tan (\alpha)=\frac{y}{x} \\ \tan (\alpha)=\frac{331.59}{282.53} \\ \tan (\alpha)\approx1.1736 \\ \alpha=\arctan (1.1736) \\ \alpha=49.56\degree \end{gathered}

If we want to express it from N to E, we substract the angle from 90°:

\beta=90\degree-\alpha=90-49.56=40.44\degree

Answer: the final location can be represented with the vector (282.53, 331.59).

1) The distance from the origin is 435.63 miles and

2) the direction is N-40°-E.

7 0
1 year ago
What is the first step in solving ln(x − 1) = ln6 − lnx for x?
Zarrin [17]
The first step to solving this problem is Multiplying In(x-1).
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