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3 years ago

Hey! Im counting on you guys!

Mathematics

2 answers:

raketka [301]3 years ago

6 0

Answer:

Ken is faster by 1 mile per hour

Step-by-step explanation:

Ken's speed

174/3 = 58 mph

Brenda's speed

57 mph as per formula

Comparing the values, we see that

Ken is faster by 58 - 57 = 1 mile per hour

Slav-nsk [51]3 years ago

4 0

Answer:

To find Ken's speed divide total distance by total time:

174 miles / 3 hours = 58 miles per hour.

In the equation for Brenda, the 57 is the miles per hour because you would multiply that by x ( hours) to get total miles (y).

Ken had the faster driving speed.

Step-by-step explanation:

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Write the missing number under each tick mark on the number line.

Setler79 [48]

Answer:

Step-by-step explanation:

4 0

2 years ago

3 consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third

den301095 [7]

Answer:

Consecutive odd integers are 19 , 21 & 23

Step-by-step explanation:

Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).

According to the question,

$2x + 3(x + 2) = 2(x + 4) + 55$

$= > 2x + 3x + 6 = 2x + 8 + 55$

Eliminating 2x from both the sides,

$= > 3x + 6 = 63$

$= > 3x = 63 - 6 = 57$

$= > x = \frac{57}{3} = 19$

So, the consecutive odd integers are = 19 , 21 & 23.

3 0

2 years ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago

PLEASE I AM MARKING BRAINLEST!

Artemon [7]

Answer:

5, 9,13,17

Step-by-step explanation:

5 +4 +4+4

8 0

2 years ago

Read 2 more answers

A standard showerhead in Sonia's house dispenses 12 gallons of water per minute. Sonia changed this showerhead to an energy-savi

diamong [38]

Sonia saves a lot of water. To figure this out, you plug the number 8 into the equation, replacing it with the variable x. y = 3(8). Therefore, y=24. To find out how much water she saves, you have to also figure out how much water she was using for 8 minutes with the other shower head, the one that wastes the water. Since it dispenses 12 gallons per minute, you multiply that by 8 minutes and get 96. Subtract 24 from 96 and get 72. Which I think is your answer. Then again, I'm in high school so I most likely am wrong.

7 0

3 years ago