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Ronch [10]
2 years ago
7

8) Which of the following is equivalent to 33 + 77

Mathematics
1 answer:
sergiy2304 [10]2 years ago
3 0
The answer is 11(3+7) duh
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In a random sample of 1,000 high-school students, 29 percent indicated that they had read the Declaration of Independence at lea
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Answer:

c. Ninety-five percent of the time, the percentage of those questioned who have read the Declaration of Independence would likely be between 25 and 33 percent.

Step-by-step explanation:

Margin of error:

"It means the percentage difference of the result above or below the exact value."

i.e. 4 percent of margin error in the question means that the result will be either 4 percent above the 29 percent or 4 percent below the 29 percent.

OR "the result can vary upto 4 percent above or below the 29 percent."

Let me simplify the answer first in number then convert it percent to understand easily.

29 percent of 1000=  (29/100)*1000=290

4 percent of 1000=(4/100)*1000=40

If 290 students had read the declaration of independence at least once with 40 margin of error, then it means the number of students that had read declaration of independence may be 330 or 250

250 is 25% of 1000 and 330 is 33% of 1000, that is why ninety-five percent of the time, the percentage of those questioned who have read the Declaration of Independence would likely be between 25 and 33 percent.

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Matthew is throwing a pizza party. He pounds of cheese available and he
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Answer:

6 Pizzas

Step-by-step explanation:

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Please help, ill give 69 points <33
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Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.5 parts
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Answer:

The value of the test statistic is t = 2.1

Step-by-step explanation:

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the expected value, \sigma is the standard deviation and n is the size of the sample.

The level of ozone normally found is 7.5 parts/million (ppm).

This means that \mu = 7.5

The mean of 24 samples is 7.8 ppm with a standard deviation of 0.7.

This means that X = 7.8, \sigma = 0.7, n = 24

Test Statistic:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{7.8 - 7.5}{\frac{0.7}{\sqrt{24}}}

t = 2.1

The value of the test statistic is t = 2.1

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123,10kg to the nearest kg​
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Answer:123,000

Step-by-step explanation:

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