Since
The square root of 11 is somewhere between 3 and 4. In order to round it to the nearest tenth, we have to try all numbers between 3 and 4 with one decimal digit, and see which is closest to 11 when squared. We have
![\begin{array}{c|c}n&n^2\\3&9\\3.1&9.61\\3.2&10.24\\3.3&10.89\\3.4&11.56\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7Dn%26n%5E2%5C%5C3%269%5C%5C3.1%269.61%5C%5C3.2%2610.24%5C%5C3.3%2610.89%5C%5C3.4%2611.56%5Cend%7Barray%7D%5Cright%5D)
So, the square root of 11 is somewhere between 3.3 and 3.4.
Answer:
-30
Step-by-step explanation:
-15 - (-8) - (-23) – 46
When u have 2 negatives it will always make a positive -(-)
<u><em>-15 + 8 </em></u>+ 23 - 46
<u><em>-7 + 23 </em></u>- 46
<u><em>16 - 46</em></u>
-30
Hope this helped!
Have a supercalifragilisticexpialidocious day!
2,2,6,7,9,11,14
And the Median is 7
Answer:
think it's c because it's 5 times -2 in other terms so
