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2 years ago

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

1 answer:

5 0

1st term
A (1) = -6+(1-1)(6)
= -6 +0
= -6

4th term
A (4)= -6 +(4-1)(6)
=-6 + 18
= 12

10th term
A (10) =-6 +(10-1)(6)
=-6 + 54
=48.

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The value of a three digit number if the tens digit is c, the hundreds digit is three less than the tens and the ones digit is 0

raketka [301]

Answer:690 580 470 360 250 140

Step-by-step explanation:

These digits are all numbers that the hundreds digit is three less than the tens digit, the ones digit is also zero

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2 years ago

Which graph represents the equation y =<br> 1/2x+3?

nalin [4]

Answer:

A, it starts at 3 since it is non proportional as well as being a postive graph.

Step-by-step explanation:

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2 years ago

Let K and T be the current ages of two siblings, Katie and Thomas. Katie is currently twice the age of Thomas. In 6 years, Katie

Pavlova-9 [17]

Answer:

Katie is 6 years old and Thomas is 3 years old

Step-by-step explanation:

Given that we should let K and T be the current ages of two siblings, Katie and Thomas.

If Katie is currently twice the age of Thomas then,

K = 2T

and in 6 years, Katie will be 4 times Thomas's current age then

K + 6 = 4T

Solving both equations simultaneously by substituting the value of K given in the first equation into the second

2T + 6 = 4T

Collect like terms

6 = 4T - 2T

6 = 2T

Divide both sides by 2

T = 3

Recall that K = 2T

K = 2 * 3

= 6

Hence Katie is 6 years old while Thomas is 3 years old

6 0

2 years ago

I need help!! I'll report if wrong

ss7ja [257]

Answer:

Step-by-step explanation:

2+2+3+4+5+6 = 23

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2 years ago

A jumper in the long-jump goes into the jump with a speed of 12 m/s at an angle of 20° above the horizontal. How far does the ju

weeeeeb [17]

Answer:

x = 9.5 m

Step-by-step explanation:

Given:

This problem is based on 2D motion kinematics equations:

$V_0 = 12 m/s$

$\theta = 20^0$

$g=9.8 m/s^2$

At maximum height:

$V_y = 0$

Components of initial velocity:

$V_0x = V_0 cos (\theta) =(12 )(cos (20^0)) = 11.3 m/s$

$V_0x = V_0 sin (\theta) = (12)(sin (20^0)) = 4.10 m/s$

To find time to reach maximum height:

$V_y = V_0y -gt$

Plugging in the known values:

0 = 4.10 - 9.8t

$t = \frac{-4.10}{-9.8}$

$t = 0.418 s$

Total time = 2t = 2(0.418) = 0.836 s

to find horizontal distance covered:

$x = (V_0x)(t)\\x = (11.3)(0.836)\\x = 9.5 m$

8 0

3 years ago