solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
Answer:
A & B
Step-by-step explanation:
A is spot-on because of the use of distributive property. B by the use of like terms.
We need to use Law of sine.
sin A/a = sin C/c
sin A/|CB| = sin C/|AB|
sin A/14 = sin(118⁰)/ 20
sin A = (14*sin(118⁰))/ 20
A=arcsin((14*sin(118⁰))/ 20) ≈ 38⁰
Answer:
Patel will require more orange juice = 
cups
Step-by-step explanation:
Patel needs the orange juice for his family = 3 cups
He needs more orange juice = 3 cups - Sum of juice squeezed from different oranges
L.C.M. of the denominators = 660
= 
=
Therefore, amount of orange juice required more = cups
Answer:
750
Step-by-step explanation:
10 times 5 times 15
