Answer:
By hypotenuse - side test (HL) the two triangles are congruent.
Step-by-step explanation:
In ∆ABC and ∆DCB
i) angleABC = angleDCB.....(each 90°)
ii) BC = BC .....( common side)
iii) AC = DB.....(given)
therefore by hypo-side test ∆ABC congruent ∆DCB
Step-by-step explanation:
1. Distribute the -2. multiply-2 with 5x and 8. it will be -10x-16=14+6x. For me, i make small numbers negative or positive than big ones. Add 16 to both sides. it will be -10x=30+6x. Subtract 6x. -10x-6x=-16x. Divide both sides by 16. x=30/16= 1 and 14/16
1/a
The b^-3 in the denominator and numerator cancel out
Answer:
x² + 18x +81
x² - 14x +49
4x²- 4x - 1
Step-by-step explanation:
multiply the x in the first parentheses by x and 9 in the other parentheses and
multiply the 9 in the first parentheses by x and 9 in the other parentheses and add all together
(x+9)(x+9)
x² + 9x + 9x + 81
x² + 18x +81
multiply the x in the first parentheses by x and -7 in the other parentheses and multiply the -7 in the first parentheses by x and -7 in the other parentheses and add all together
(x-7)(x-7)
x² -7x - 7x +49
x² - 14x +49
(2x-1)² is the same as (2x-1)(2x-1)
multiply the 2x in the first parentheses by 2x and -1 in the other parentheses and multiply the -1 in the first parentheses by 2x and -1 in the other parentheses and add all together
(2x-1)(2x-1)
4x²-2x-2x+1
4x²- 4x - 1
