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Fed [463]
3 years ago
14

The region of africa in which zebras, elephants, wildebeests, antelope and other large animals live is known as the taiga. tropi

cal savanna. tropical rain forest. midlatitude steppe.
Biology
2 answers:
Sladkaya [172]3 years ago
8 0

Answer:

Tropical savanna.

Explanation:

The tropical savanna fauna is formed by large herbivores such as buffalo, giraffes, kangaroos, elephants and antelopes (elande, impala, gazelle, kudu, orix, etc.), also featuring zebras and wildebeest. These herbivores serve as food for carnivores such as lions, tigers, leopards, wild dogs and others. Underground behavior is observed in smaller animals such as reptiles and amphibians, which protect themselves from unnecessary water loss. There are numerous bird species such as the eagle, the ostrich and the hawk.

Tropical savannas suffer from human interference. Extensive areas of this biome are used for pasture development and agriculture. Intensive grazing totally eliminates grasses, turning the savannah into a desert. Many animals are threatened with extinction due to habitat loss and poaching such as zebra, rhino, lion and elephant.

Elodia [21]3 years ago
3 0

The answer is tropical savanna. The region’s ecosystem is characterized by tall grasses, shrubs, and a scattered distribution of trees (especially acacia trees). Large regions of tropical savanna extend through the nations of Botswana, Namibia, and Kenya in Africa. Savannas are also characterized by seasonal water availability, with the majority of rainfall confined to one season. They are frequently found in transitional zones between forest and desert or grassland.






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In humans, MN blood types are determined by an autosomal gene with two alleles: LM and LN. In one population of 592 people, ther
RoseWind [281]

Answer:

148

Explanation:

According to Hardy-Weinberg equilibrium,

p + q = 1

p² + 2pq + q² = 1 where,

p = frequency of dominant allele

q = frequency of recessive allele

p² = frequency of homozygous dominant genotype

2pq = frequency of heterozygous genotype

q² = frequency of homozygous recessive genotype

Here,

Total population = 592

Number of NN people = 148

Frequency of N blood group or NN genotype (q²) = 148/592 = 0.25

q = √0.25 = 0.5

p = 1 - q

= 1 - 0.5 = 0.5

Hence, p = 0.5

Frequency of MM genotype = p² = 0.25

Number of people with MM genotype = 0.25*592 = 148

Hence, 148 people will have MM genotype or M blood group.

5 0
3 years ago
If a mutation occurred in SODD that prohibited its interaction with the DD of TNF receptor, the TNF receptor would
Xelga [282]

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4 years ago
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Answer: Base pairs are formed when adenine forms a hydrogen bond with thymine, or cytosine forms a hydrogen bond with guanine. The second part of a nucleotide is the phosphate, which differentiates the nucleotide molecule from a nucleoside molecule.

Explanation:

7 0
3 years ago
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Glucose is virtually the sole fuel for the human brain, except during prolonged starvation. The brain lacks fuel stores, thus requires a continuous supply of glucose. It consumes about 120 g daily which corresponds to an energy input of 420 kcal (1760 KJ), accounting for some 60% of the utilization of glucose by the whole body in the resting state. 
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Please help ASAP!! A mining company's reclamation plan is not permitted because there is no evidence that funding has been secur
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Answer:

Cost Issue

Explanation:

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7 0
3 years ago
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