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kolbaska11 [484]
3 years ago
7

Greatest common factor 44x^5 30x

Mathematics
1 answer:
Masja [62]3 years ago
3 0
44x^5=\boxed{2x}\cdot22x^4\\\\30x=\boxed{2x}\cdot15\\\\GCF(44x^5;\ 30x)=2x
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Write in the measure, in degrees, for each angle marked with a question mark.​
garik1379 [7]

1. 180-146=34°

2. 40° (alternate angles are equal)

3. 50° (vertically opposite angles are equal)

4. 180-75=105° (co-interior angles add up to 180°)

5. 90-65=25°

Hope my answer helped u :)

3 0
3 years ago
6) If sec theta+tan theta = P. PT sin theta=P^2-1/P^2+1 ...?
jarptica [38.1K]
I will use the letter x instead of theta.

Then the problem is, given sec(x) + tan(x) = P, show that

sin(x) = [P^2 - 1] / [P^2 + 1]

I am going to take a non regular path.

First, develop a little the left side of the first equation:

sec(x) + tan(x) = 1 / cos(x) +  sin(x) / cos(x) = [1 + sin(x)] / cos(x)

and that is equal to P.

Second, develop the rigth side of the second equation:

[p^2 - 1] / [p^2 + 1] =

= [ { [1 + sin(x)] / cos(x) }^2 - 1] / [ { [1 + sin(x)] / cos(x)}^2 +1 ] =

=  { [1 + sin(x)]^2 - [cos(x)]^2 } / { [1 + sin(x)]^2 + [cos(x)]^2 } =

= {1 + 2sin(x) + [sin(x)^2] - [cos(x)^2] } / {1 + 2sin(x) + [sin(x)^2] + [cos(x)^2] }

= {2sin(x) + [sin(x)]^2 + [sin(x)]^2 } / { 1 + 2 sin(x) + 1} =

= {2sin(x) + 2 [sin(x)]^2 } / {2 + 2sin(x)} = {2sin(x) ( 1 + sin(x)} / {2(1+sin(x)} =

= sin(x)

Then, working with the first equation, we have proved that [p^2 - 1] / [p^2 + 1] = sin(x), the second equation.


4 0
4 years ago
The answer to 15ft long and 8ft wide
g100num [7]
The answer to that will be 23
7 0
4 years ago
What is y=4x^2-9x+1 in vertex form
Anna11 [10]

Answer:

y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}

Step-by-step explanation:

y = 4x^2 - 9x + 1

You need to complete the square on the right side.

y = (4x^2 - 9x) + 1

y = 4(x^2 - \dfrac{9}{4}x) + 1

y = 4 \left( x^2 - \dfrac{9}{4}x + \left( \dfrac{9}{8} \right)^2 \right) + 1 - 4\left( \dfrac{9}{8} \right)^2

y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - 4 \left( \dfrac{81}{64} \right)

y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - \dfrac{81}{16}

y = 4 \left(x - \dfrac{9}{8} \right)^2 + \dfrac{16}{16} - \dfrac{81}{16}

y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}

3 0
3 years ago
The length of the ladder that will run from the ground to the door of the tree house is nine feet. The plan recommends that the
Gwar [14]

Answer:

13 Rungs

Step-by-step explanation:

According to the Question,

  • Given, The length of the ladder that will run from the ground to the door of the treehouse is 9 feet ( 9 × 12 = 108 inches).

The plan recommends that the rungs of the ladder be spaced at 8-inch intervals.

  • And, The first and last rung should be 6 inches from the respective ends.

Thus, the rungs Cover on 108 -(6+6) = 96 inches with 8-inch gaping between each rung.

  • Therefore, the Total Rungs on the treehouse ladders have (96/8)+1 ⇒ 13 Ladders.
7 0
3 years ago
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