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3 years ago

Evaluate the following expression (-3)^2

Mathematics

1 answer:

Cloud [144]3 years ago

8 0

Answer:

Step-by-step explanation:

negative times a negative is a positive. Negative three squared is 9.

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Mrs.rosso has to travel 390 miles on a highway. she drives 130 miles in 2 hours

Zielflug [23.3K]

Hi,

first you should divide 130 (speed) by 2 (time), then divide 390 by 65 (result of 130 / 2)

8 0

4 years ago

Ashley drove 864 miles in 12 hours, at the same rate how mnay would she drive in 9 hours?

loris [4]

864/12 = the rate per hour, which would be 72 mph. To find how many miles she would drive at the same rate, multiply the 72 (miles) with 9 (hours) which is equal to 648 miles

5 0

3 years ago

Which of the point-slope equations below are correct for the line that passes through points (-4,-14) and (1,3)?

Scrat [10]

(-4,-4)(1,3)
slope = (3 - (-4) / (1 - (-4)
slope = (3 + 4) / (1 + 4) = 7/5

y - y1 = m(x - x1)...using (-4,-4)
slope(m) = 7/5
y - (-4) = 7/5(x - (-4) =
y + 4 = 7/5(x + 4) <==here is one

y - y1 = m(x - x1)..using (1,3)
slope = 7/5
y - 3 = 7/5(x - 1) <== here is the other one

4 0

3 years ago

The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.

Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

$P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z$

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

$P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z$

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

$P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0$

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0

3 years ago

The transformation that can result in a figure that is NOT congruent to the original is:

ddd [48]

Dilation because the sides will not be the same size as the original

6 0

4 years ago

Read 2 more answers