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IgorLugansk [536]
4 years ago
11

Please help me with this math problem.

Mathematics
1 answer:
garri49 [273]4 years ago
7 0

Answer:

-x + 8y = 56

Step-by-step explanation:

To get rid of fractions, multiply equation by 8.

It becomes 8y = x + 56

Now get the x to the side with the 8y by subtracting x.

-x + 8y = 56

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If you don’t know then don’t say anything.
tino4ka555 [31]

Answer:

in total there are 80 subjects. I don't know what class width is though.

Step-by-step explanation:

Look at the graph

3 0
3 years ago
If C is the incenter of ∆AMD, m∠A M C = 3 x + 6 and m∠ DMC= 8 x − 49.
Alexus [3.1K]

Answer:

3x+6=8x-49,

-6. -6

__________

3x=8x-55

-8x. -8x

________

-5x=-55

x=11,

3(11)+6=39

8(11)-49=39

Step-by-step explanation:

5 0
3 years ago
an old treasure map has the following instructions stand next to the black rock and face west. Walk 20 yards and then turn 90 de
Elza [17]

Answer:

West.

Step-by-step explanation:

An old treasure map has the following instructions: stand next to the black rock and face west. Walk 20 yards and then turn 90 degrees clockwise. Walk another 10 yards and then turn 45 degrees anticlockwise. Walk another 15 yards, reverse your directions and walk 5 yards back. Turn 135 degrees clockwise and walk another 10 yards. To determine in which direction you are now facing, the following logical reasoning must be carried out:

You start by walking 20 yards west, then turning 90 degrees clockwise, turning south. Then you walk 10 yards and turn counterclockwise 45 degrees, to the southwest. Later, you walk another 15 yards, turn the direction to the northeast, and walk 5 more yards. From the northeast turn 135 degrees clockwise to the west and walk 10 yards. Thus, the final sense in which the person is walking is to the West.

6 0
3 years ago
The width of a rectangular painting is 3 in. less than the length. The area of the painting is 40 in ^2 .Find the length and wid
Amiraneli [1.4K]

Answer:

Mark me as brainlist

Step-by-step explanation:

a) (h + 5)(2h + 8) is the expression for the combined area of the painting and frame

b) The combined area when h = 12 is 544 square inches

c) The combined area when h = 15 is 760 square inches

Solution:

Given that,

A frame that is 2.5 inches wide goes around the painting

The frame will go around all 4 sides of the painting.

That means that the length of each side of the painting will increase by 2.5 inches

Therefore,

The height of painting and frame is:

h = h + 2.5 + 2.5

h = h + 5

(2.5  inches on the top and the bottom)

Also given that,

Width of a rectangular painting is 3 inches more than twice the height

w = 3 + 2h

Now the width of painting and frame is:

w = 3 + 2h + 2.5 + 2.5

(Again, 2.5 inches on the top and the bottom)

w = 2h + 8

Thus the combined area of the painting and frame is:

B) Substitute h = 12 inches

Thus the combined area when h = 12 is 544 square inches

C) Substitute h = 15 inches

Thus combined area when h = 15 is 760 square inches

6 0
3 years ago
What is the diameter of the circle with 49 pi
Bogdan [553]
Area = \pi r^2\\ 49\pi = \pi r^2\\49=r^2\\ r=7\\\\ Diameter = 14 Remember, diameter = 2 x radius
3 0
4 years ago
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