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Phoenix [80]
3 years ago
13

If you don’t know then don’t say anything.

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0

Answer:

in total there are 80 subjects. I don't know what class width is though.

Step-by-step explanation:

Look at the graph

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The lines y1 = 2x - 6, y2 = -3x + 4, y3 = -1/2x + 4 are the sides of a right triangle. Find the perimeter and area of the triang
sergiy2304 [10]

The area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

<h3>Perimeter and area of the triangle giving the equation of a line</h3>

First we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.

From the given equation of the lines, the points of intersection of the line are (x₁, y₁) = (- 0.4, 5.2), (x₂, y₂) = (-0.8, 4.4) and (x₃, y₃) = (0, 4)

For the base

b² = c² -a²

b = √(-0.8)² + (4 - 4.4)²

b = 2√5 / 5

For the height

h = √((- 0.4) - (- 0.8))² + (5.2 - 4.4)²

height = 2√5 / 5

For the hypotenuse

r = √2 · b

r = 2√10 / 5

<h3>Determine the Perimeter and area</h3>

Perimeter = s1+s2+s3

Perimeter = 2√5 / 5 + 2√5 / 5 + 2√10 / 5

Perimeter = (2√10 + 4√5) / 5 units

<u>For the area</u>

area = 1/2* base * height

A = 0.5 · (2√5 / 5) · (2√5 / 5)

A = 2/5 square units

Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

Learn more on area and perimeter of triangles here: brainly.com/question/21511715

#SPJ1

8 0
2 years ago
Find the midpoint (8, -6) (6,5)​
andrey2020 [161]
I think it’s (7, -0.5)
7 0
2 years ago
I'm giving branliest 2X - 3y = 12 in a standard and point slope form ​
iogann1982 [59]
In slope intercept form it is y=2/3x-4
In point slope form it is 2/3x-y-4 :)
5 0
3 years ago
What are the vertices of triangle A'B'C' produced by (x, y) -&gt; (x+5, y-2)?
lara [203]

Answer:

The vertices of triangle A'B'C' produced by (x, y)  →  (x+5, y-2)  will be:

  • A'(8, -2)
  • B'(8, 0)
  • C'(5, -5)

Step-by-step explanation:

Given the vertices of an original triangle ΔABC such that

  • A = (3, 0)
  • B = (3, 2)
  • C = (0, -3)

As the rule of translation is given by

Translation: (x, y)  →  (x+5, y-2)

So, after the translation the vertices of the original triangle ΔABC will be translated as:

A = (3, 0)  → (x+5, y-2)  ⇒ (3+5, 0-2) = A'(8, -2)

B = (3, 2)  →  (x+5, y-2)  ⇒ (3+5, 2-2) = B'(8, 0)

C = (0, -3) → (x+5, y-2)  ⇒ (0+5, -3-2) = C'(5, -5)

Therefore, the vertices of triangle A'B'C' produced by (x, y)  →  (x+5, y-2)  will be:

  • A'(8, -2)
  • B'(8, 0)
  • C'(5, -5)
7 0
3 years ago
Please help it is algebraic properties of limits!
Lyrx [107]

Answer:

Hi, I'd be happy to help. Is there a photo you can attach of the problem you need help with?

8 0
3 years ago
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