2.2 = z ÷ 57 A() 62.7 B() 125.4 C() 59.2 D() 54.8

What is 16kg +2,800g

stira [4]

The answer is 18,800 g

16kg is the same as 16,000g Then add that to 2,800g

7 0

3 years ago

What is the answer for this -6+x=-11

Mars2501 [29]

Answer:

x = -5

Step-by-step explanation:

-6 + x = -11

x = -11 + 6

x = -5

8 0

3 years ago

Read 2 more answers

The diameter of a human hair is 9 \cdot 10^{-5}9⋅10 −5 9, dot, 10, start superscript, minus, 5, end superscript meters. The diam

OlgaM077 [116]

Given that the diameter of a human hair $= 9 \times 10^{-5}$

Given that the diameter of a spider's silk $= 3 \times 10^{-6}$

Now we have to find how much greater is the diameter of a human hair than the diameter of a spider's silk.

To find that we just need to subtract the given numbers.

$9 \times 10^{-5} - 3 \times 10^{-6}$

Since powers are not same so let's make them equal

$= 90 \times 10^{-6} - 3 \times 10^{-6}$

now we can easily subtract the coefficients that is 3 from 9

$= (90-3) \times 10^{-6}$

$= 87 \times 10^{-6}$

$= 8.7 \times 10^{-5}$

Hence final answer is $8.7 \times 10^{-5}$ .

7 0

4 years ago

A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for

Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

$\implies h=\frac{1}{w^2}$

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

$= 2\times \frac{1}{w^2}(w+2w)$

$=\frac{6w}{w^2}$

$=\frac{6}{w}$

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

$C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}$

$=2w^2+4w^2+\frac{12}{w}$

$=6w^2+\frac{12}{w}$

Differentiating with respect to w,

$C'(w) = 12w -\frac{12}{w^2}$

Again differentiating with respect to w,

$C''(w) = 12 + \frac{24}{w^3}$

For maxima or minima,

C'(w) = 0

$\implies 12w -\frac{12}{w^2}=0$

$\implies 12w^3 - 12=0$

$w^3-1=0\implies w = 1$

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0

4 years ago

Expand- 2.5( - 3+ 4n + 8)

Ivan

Answer:

10n + 12.5

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

2.2 = z ÷ 57A() 62.7B() 125.4C() 59.2D() 54.8