9514 1404 393
Answer:
7.83 km/h
Step-by-step explanation:
At her constant pace, Nina's time for 6 km will be found by the proportion ...
(time for 6 km)/(6 km) = (time for 9 km)/(9 km)
time for 6 km = (6 km)/(9 km) × (75 min) = 50 min
Jo's time for the same distance will be 4 minutes less: 50 -4 = 46 min. Jo's speed is ...
speed = distance/time
= (6 km)/(46/60 h) = 360/46 h ≈ 7.83 km/h . . . . Jo's speed
_____
<em>Additional comment</em>
From the 6 km point, the remaining race is half the distance already run, so will take half the time already taken. As we know, Nina will finish in 25 more minutes; Jo will finish in 46/2 = 23 more minutes, 2 minutes ahead of Nina.
This means common members {10,40,60}
Answer:
one solution with a y value of 5
Step-by-step explanation:
/| x+y-4 = 0| x-y-6 = 0
We try to solve the equation: x+y-4 = 0
x+y-4 = 0 // - x-4
y = -(x-4)
y = 4-x
We insert the solution into one of the initial equations of our system of equations
We get a system of equations:
/| x+x-6-4 = 0| y = 4-x
2*x-10 = 0 // + 10
2*x = 10 // : 2
x = 10/2
x = 5
We insert the solution into one of the initial equations of our system of equations
For y = 4-x:
y = 4-5
y = -1
We get a system of equations:
/| y = -1| x = 5
Answer:
The solution of the system is the ordered pair (-13,-4)
Step-by-step explanation:
we have
-----> equation A
----> equation B
Solve the system by elimination
Multiply by 2 both sides equation B
----> equation C
Adds equation A and equation C
<em>Find the value of a</em>
substitute the value of b in any equation (i take equation B)
therefore
The solution of the system is the ordered pair (-13,-4)
Answer:
This equation is in standard form: ax 1+bx+c=0. Substitute 9 for a, 16 for b, and −112 for c in the quadratic formula 2a−b±b2−4ac.x= 2×9−16± 16^2−4×9(−112)Square 16.x=2×9−16±256−4×9(−112) Multiply −4 times 9.x=2×9−16± 256−36(−112) Multiply −36 times −112.x=2×9−16±256+4032 Add 256 to 4032.x=2×9−16±4288 Take the square root of 4288.x=2×9−16±8+67 Multiply 2 times 9x=18−16±8=67
Step-by-step explanation:
hope this help if not let me know
