Question

Y varies jointly with x. Y=16 when x=4 and z=1/2. Find y when x=2 and z=1/4. Enter the value of y in the box. Picture attached, 15 points and I'll give Brainliest! Due in two hours.

Answer 1

Answer:

y = 4

Step-by-step explanation:

Given that y varies jointly with x and z then the equation relating them is

y = kxz ← k is the constant of variation

To find k use the condition y = 16 when x = 4 and z = $\frac{1}{2}$ , that is

16 = k × 4 × $\frac{1}{2}$ = 2k ( divide both sides by 2 )

8 = k

y = 8xz ← equation of variation

When x = 2 and z = $\frac{1}{4}$ , then

y = 8 × 2 × $\frac{1}{4}$ = 16 × $\frac{1}{4}$ = 4