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3 years ago

8

Jamal owns a parking garage and is trying to find the relationship between hour of the day and number of cars in the garage. He

finds that between 4 am and 10 am he can model this with a linear relationship. The equation for this model is y = 3.96x + 2. About how many cars are entering the garage every hour?
A) 1
B) 2
C) 3
D) 4

2 answers:

Sphinxa [80]3 years ago

4 0

Jamal owns a parking garage and is trying to find the relationship between hour of the day and number of cars in the garage. He finds that between 4 am and 10 am he can model this with a linear relationship. The equation for this model is y = 3.96x + 2.

Given the equation the slope is the rate of car enters the garage. So it is 3.96 about 4 cars per hour

maw [93]3 years ago

3 0

it is 3.96 about 4 cars per hour

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Linear equations. write the standard form of an equation of the

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Answer:

The standard form of an equation of the line that passes through the given point having slope is $y-y_{1} =m(x-x_{1}$

Step-by-step explanation:

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$y-y_{1} =m(x-x_{1}$

another form of an equation of the line that passes through the given point ( $(x_{0} ,y_{0} )$ and having slope m is

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3 years ago

Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral

MAVERICK [17]

Answer:

a. $\frac {2} {s-1}$ converges to s> 1.

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d. $\frac {s}{s^2 + 25}$ converges to s> 0.

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g. $-\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $\frac {1} {s ^ 2 + 4}$ converges to s> 0.

Step-by-step explanation:

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c. $L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3}$ converges to s> - 3.

d. $L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25}$ converges to s> 0.

e. $L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1}$ converges even s> 0.

f. $L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4}$ converges to s> 0.

g. $L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4}$ converges to s> 0.

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3 years ago

Which of these points lies on the circle with the center (2,3) and radius 2?

yan [13]

Answer:

The answer to your question is the letter A.

Step-by-step explanation:

Data

Center = (2, 3)

radius = 2

Process

1.- Find the equation of the line

(x - h)² + (y - k)² = r²

-Substitution

(x - 2)² + (y - 3)² = 2²

-Simplification

(x - 2)² + (y - 3)² = 4

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A. (4, 3)

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B (-1, 0)

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(-1)² + (0)² = 4

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D. (3, 4)

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3 years ago

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valkas [14]

<u>Answer:</u>

225 ft²

<u>Steps:</u>

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3 years ago

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the first three steps of completing the square to solve the quadratic equation X2+4X-6=0 are shown below. what re the next 3 ste

Vilka [71]

Answer:

see the explanation

Step-by-step explanation:

<u><em>The complete question is</em></u>

The first three steps of completing the square to solve the quadratic equation x2 +4x -6= 0, are shown below.

Step 1: x2 +4x= 6

Step 2: x2 +4x+4=6+4

Step 3: (x +2)^2=10

What are the next 3 steps?

we have

step 4

Take square root both sides

$\sqrt{(x+2)^2} =\sqrt{10}$

step 5

Simplify

$x+2=\pm\sqrt{10}$

step 6

Solve for x

subtract 2 both sides

$x=-2\pm\sqrt{10}$

$x_1=-2+\sqrt{10}$

$x_2=-2-\sqrt{10}$

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3 years ago