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3 years ago

10

Jaime used a microscope to measure the diameter of a hair. She found the diameter of her hair was 0.000072 meter. How is this nu

mber written in scientific notation?

2 answers:

Dennis_Churaev [7]3 years ago

3 0

Answer:

7.2 × 10 ^-5

Step-by-step explanation:

Google

Anestetic [448]3 years ago

3 0

Answer:

7.2 × 10 with an exponent of -5

Step-by-step explanation:

the answer is 7.2×10 with an exponent of -5

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A study has shown that the daily amount of milk produced by a dairy cow is normally distributed, with a mean of 6.2 gallons and

V125BC [204]

Answer:

5.5 gallons to 6.9 gallons

Step-by-step explanation:

Daily a cow

produces a mean of 6.2 gallons (average

of 6.2 gallons, meaning they already

found the mean, "averaged" it out for

you) with a deviation of 7 gallons ("give

or take" .7 gallons). On any given day

(throw these words out) 68% of the cows

(don't need this information to answer

the question either, thrown in to confuse

you) will produce an amount of milk

within which of the following ranges?

Just subtract the deviation ("give or

take number").7 gallons from the mean

(average (already determined)) 6.2

gallons which is 5.5 gallons THEN add

the deviation ("give or take number").

7 gallons to the mean (average (already

determined)) 6.2 gallons which is 6.9

gallons. Your answer is A 5.5 gallons to

6.9 gallons. You don't even have to go

crazy on the math on this question you

can rule them all out but A immediately

with subtracting .7 from 6.2.

hope it helps!

4 0

3 years ago

Read 2 more answers

For this question I am sure the answer is 81% as you divide 45 and 55. However, it is stating my answer is incorrect even though

77julia77 [94]

Answer:

it says round to the nearest 10th so it wouldn't be 81, it would be 81.8%

8 0

2 years ago

A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has fa

gayaneshka [121]

Answer:

the probability the die chosen was green is 0.9

Step-by-step explanation:

Given that:

A bag contains two six-sided dice: one red, one green.

The red die has faces numbered 1, 2, 3, 4, 5, and 6.

The green die has faces numbered 1, 2, 3, 4, 4, and 4.

From above, the probability of obtaining 4 in a single throw of a fair die is:

P (4 | red dice) = $\dfrac{1}{6}$

P (4 | green dice) = $\dfrac{3}{6}$ = $\dfrac{1}{2}$

A die is selected at random and rolled four times.

As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = $\dfrac{1}{2}$

The probability of two 1's and two 4's in the first dice can be calculated as:

= $\begin {pmatrix} \left \begin{array}{c}4\\2\\ \end{array} \right \end {pmatrix} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^4$

= $\dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4$

= $\dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4$

= $6 \times ( \dfrac{1}{6})^4$

= $(\dfrac{1}{6})^3$

= $\dfrac{1}{216}$

The probability of two 1's and two 4's in the second dice can be calculated as:

= $\begin {pmatrix} \left \begin{array}{c}4\\2\\ \end{array} \right \end {pmatrix} \times \begin {pmatrix} \dfrac{1}{6} \end {pmatrix} ^2 \times \begin {pmatrix} \dfrac{3}{6} \end {pmatrix} ^2$

= $\dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times ( \dfrac{3}{6})^2$

= $6 \times ( \dfrac{1}{6})^2 \times ( \dfrac{3}{6})^2$

= $( \dfrac{1}{6}) \times ( \dfrac{3}{6})^2$

= $\dfrac{9}{216}$

∴

The probability of two 1's and two 4's in both dies = P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )

The probability of two 1's and two 4's in both die = $\dfrac{1}{216} \times \dfrac{1}{2} + \dfrac{9}{216} \times \dfrac{1}{2}$

The probability of two 1's and two 4's in both die = $\dfrac{1}{432} + \dfrac{1}{48}$

The probability of two 1's and two 4's in both die = $\dfrac{5}{216}$

By applying Bayes Theorem; the probability that the die was green can be calculated as:

P(second die (green) | two 1's and two 4's ) = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)

P(second die (green) | two 1's and two 4's ) = $\dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}$

P(second die (green) | two 1's and two 4's ) = $\dfrac{0.5 \times 0.04166666667}{0.02314814815}$

P(second die (green) | two 1's and two 4's ) = 0.9

Thus; the probability the die chosen was green is 0.9

8 0

3 years ago

John accepted a reduction of 15% on his salary when his company was not doing well. Now his company's financial position has imp

o-na [289]

To reverse a percentage decrease you divide it by the decrease (+ 100%)
For example we will pick the number, 100, which is decreased by 15% to 85.

To make 85 back to 100 we divide it by the decrease (1-0.15):
85 / 0.85 = 100

To find out how much 85 increased to get back to 100, we do:
15 / 85 = 0.1765 = %17.65

15 is the reduction/difference, and 85 is the with reduction total.

Because percentages stay the same, this is applicable to any numbers, from this, we know that whenever something is reduced by 15% - when restored to it's original is increased by %17.65

The answer is %17.65

6 0

3 years ago

Haley practiced her free throws at the basket ball court and shot 25 times. She made 11 of her shots. What percent of her shots

ivolga24 [154]

Answer:

<h2>56% </h2>

Step-by-step explanation:

Haley practiced her free throws at the basket ball court and shot 25 times

She made 11 of her shots.

find: What percent of her shots did she NOT make?

<u>11 shots made</u> = 44%

25 shots

100% - 44% = 56%

therefore, 56% of her shot did NOT make it.

8 0

3 years ago