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astra-53 [7]
3 years ago
7

Select the GCF of these numbers. 2^5 · 5· 11 and 2^3· 5^2 · 7

Mathematics
1 answer:
Lunna [17]3 years ago
8 0
I hope this helps you

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A mother shares a box of 20 chocolates in the same ratio as her children's ages . Calculate how many chocolates each child gets
Anni [7]
So a box of 20 chocolates is divided between a group of people based on age So the ratio for Sibusiso, Dorris, and Freddy is 2:3:5 Add these together, and you get 10 So to find how much each person gets, divide total amount of chocolates by total age So (20÷10) = 2 So multiply each age term by 2 and you have your answer (4:6:10) So Sibusiso gets 4, Dorris gets 6 and Freddy gets 10
8 0
3 years ago
$11.13-$5.50-$6.12=$10.51; $30- $10.51
MrMuchimi
What is the problem?? I would love to help
3 0
3 years ago
Choose the three shapes that have an area of 36 square centimeters
Artemon [7]

Choose the three shapes that have and Area of 36 square centimeters

Step-by-step explanation:

3 0
3 years ago
The coefficient of x^ky^n-k in the expansion of (x+y)^n equals (nk). True or false.
AVprozaik [17]

Answer:

The correct option is;

False

Step-by-step explanation:

The coefficient of x^k·y^(n-k) is nk,   False

The kth coefficient of the binomial expansion, (x + y)ⁿ is  \dbinom{n}{k} = \dfrac{n!}{k!\cdot (n-k)!} = C(n,k)

Where;

k = r - 1

r = The term in the series

For an example the expansion of (x + y)⁵, we have;

(x + y)⁵ = x⁵ + 5·x⁴·y + 10·x³·y² + 10·x²·y³ + 5·x·y⁴ + y⁵

The third term, (k = 3) coefficient is 10 while n×k = 3×5 = 15

Therefore, the coefficient of x^k·y^(n-k) for the expansion  (x + y)ⁿ = C(n,k) not nk

7 0
2 years ago
One-fourth of a number and 6 is the same as 3 subtracted from the number itself
ratelena [41]

Answer:

I'm not the greatest at math but I'll see if I can get this right.

I'm super sorry if this is wrong

5 0
3 years ago
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