Z=-4. z+6/3=2(z/4); cancel out the 2 on the right side[2/1*z/4---2z/4---z/2]. z+6/3=z/2; cancel out the denominator of 2 on the right side[z/2*2=z \\\ 2(z+6/3)=2z+12/3=2z+4]~~I know its alot, huh? Sry...~~ z=2z+4; subtract both sides by 2z[-z=4; divide by -1; z=-4] I hope that helped.
HELLO !
Okay so what you do is<em> eliminate the parenthesis </em>in the equation because it really helps
So you would multiply 8 and b
Also multiple 8 and a
You would get 8b and 8a
Your equation would look like ...
2a + 8b + 8a = ...
<em>Now you add the alike things in the equation </em>
8a and 2a are the alike things.
Now you would have ...
10a + 8b = ?
Answer:
x=−2y+3 and x=y+6
Step-by-step explanation:
x+2y=3
x+2y+−2y=3+−2y
x=−2y+3
x−y=6
x−y+y=6+y
x=y+6
Answer:
First, we need to know if AP is equal to PB. We don't really know that CP passed through the midpoint of AB. We also don't know if CPA is equal to CPB. This is why there is not enough information to state that CP is the perpendicular bisector of AB.
Step-by-step explanation:
A perpendicular bisector is a segment that passes through a midpoint of a segment and is perpendicular to it.
<em>-kiniwih426</em>
