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GREYUIT [131]
3 years ago
5

What is the value of log16 4? 4 1/2 1/4 2

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
5 0
The answer will be 1/2
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When a certain number is divided by 4, the answer is 160 with a remainder of 2. What is the number?
Veseljchak [2.6K]
X/4=160R2      X=642. I hope I helped you out.        160x4=640+2=642.
4 0
3 years ago
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{x|x€Z^x&lt;8}<br> Please someone help me what should be the elements in the set
joja [24]
What how is this a problem and how are you in middle school

5 0
3 years ago
Thank you!!!!!!!!!!!!!!!
OverLord2011 [107]

Answer:

Binomial distribution requires all of the following to be satisfied:

1. size of experiment (N=27) is known.

2. each trial of experiment is Bernoulli trial (i.e. either fail or pass)

3. probability (p=0.14) remains constant through trials.

4. trials are independent, and random.

Binomial distribution can be used as a close approximation, with the  usual assumption that a sample of 27 in thousands of stock is representative of the population., and is given by the probability of x successes (defective).

P(x)=C(N,x)*p^x*(1-p)^(n-x)

where N=27, p=0.14, and C(N,x) is the number of combinations of x items out of N.

So we need the probability of <em>at most one defective</em>, which is

P(0)+P(1)

= C(27,0)*0.14^0*(0.86)^(27) + C(27,1)*0.14^1*(0.86^26)

=1*1*0.0170 + 27*0.14*0.0198

=0.0170+0.0749

=0.0919


4 0
3 years ago
You have quarters and dimes that total $2.80. Your friend says it is possible that the number of quarters is 8 more than the num
AnnyKZ [126]

Answer:

Step-by-step explanation:

d = number of dimes

2.80 = 0.1d + 0.25 (d + 8 )

2.80 = 0.1d + 0.25d + 2            Combine like terms

2.80 = 0.35d + 2                       Subtract 2 from both sides

0.80 = 0.35d                             Divide both sides by 0.35

d ≈ 2.29

No, it's not possible to have more quarters than dimes when the total is $2.80 because it's not possible to have part of a dime.

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3 years ago
PLEASE HELP FAST!!!! 40 POINTS!!!!!!
dimulka [17.4K]
Commutative property of addition
5 0
3 years ago
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