We will see that f'(x) > 0, which means that f(x) is an increasing function.
<h3>
How to prove that the function is increasing?</h3>
For any function f(x), if f'(x) > 0, then f(x) is increasing for any value of x.
Here we have the cubic function:
f(x) = x³ + 4x
If we differentiate this, we get:
f'(x) = df(x)/dx = 3x² + 4.
And notice that x² is always positive, then f'(x) > 0, which means that f(x) is an increasing function.
If you want to learn more about cubic functions:
brainly.com/question/20896994
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I 150
ii 200
iii 350
i 50
ii 200
iii 250
Answer:
300
Step-by-step explanation:
you should muliple 60 and 5
Emma: Isosceles
Gabriel: Scalene
Jorge: idk
Makayla: Equilateral
60%. there are 365 students in total because 219+146 is 365. 219/365 is .6 meaning the percent is 60%. The percentage is the students who voted to be falcons was 60%
