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3 years ago

6. Cynthia wants to buy a round photo frame for

Mathematics

1 answer:

sineoko [7]3 years ago

4 0

Answer:

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Step-by-step explanation:

C = 2 x r x π = 2 x 9 x π = 18 π cm

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What is the common difference of the sequence below?

vagabundo [1.1K]

Answer:

Step-by-step explanation:

In finding the COMMON DIFFERENCE, subtract the 2nd term and the first term.

a1 = -4

a2 = -2

Let "d" representing the COMMON DIFFERENCE.

d = -2 -(-4)

d = -2 + 4

d = 2

ANSWER:

THE COMMON DIFFERENCE OF THIS SEQUENCE IS 2

3 0

3 years ago

Read 2 more answers

City A is 10 miles from city B and 5 miles from city C. Cities A, B, and C form a right triangle at A. A road connects cities B

laila [671]

Answer:

11.18 miles

Step-by-step explanation:

The sides of a right triangle a, b, c are related by the equation

a^2 + b^2 = c^2

where c is the longest side of the triangle

Hence given that A connects B and C directly and forms a right angle at A

5^2 + 10^2 = c^2

Where c is the length of the road

25 + 100 = c^2

125 = c^2

c = 125^1/2

= 11.18 miles

3 0

3 years ago

Write down the characteristics of culture translate into nepali language

Tatiana [17]

Answer:

can you explain more freely about question I did not understand sorry for comments in answet

6 0

3 years ago

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago

Find the difference between 430 and 144

nata0808 [166]

286. you just subtract the two numbers

5 0

3 years ago

Read 2 more answers