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avanturin [10]
3 years ago
10

Given the point (1, 3) and a slope of 2, write an equation in point-slope form.

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

y=2x+1

Step-by-step explanation:

Since we are given a point and a slope, we can use the point slope formula

y-y_{1} =m(x-x_{1})

m is the slope. In this case, m is 2.

y1 is the y coordinate of the point given. y1 is 3.

x1 is the x coordinate of the point given. x1 is 1

y-3=2(x-1)

Now, we need to get the equation into point slope form: y=mx+b

To do this, we need to get y by itself

First, distribute the 2 on the right

y-3=2*x+ 2*-1

y-3=2x-2

Add 3 to both sides

y-3+3=2x-2+3

y=2x+1

The equation is in y=mx+b form, so our final equation is:

y=2x+1

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4 0
2 years ago
4x=2 solve for X<br><img src="https://tex.z-dn.net/?f=4x%20%3D%202%20solve%20for%20x" id="TexFormula1" title="4x = 2 solve for x
Bogdan [553]
X=1/2 hope this helps <3
3 0
3 years ago
Read 2 more answers
Help pls I need answers ASAP
pishuonlain [190]

\tt Step-by-step~explanation:

To be able to solve this question, we need to know about the Pythagorean theorem: a² + b² = c². A and b represents the two sides that make the right angle, and C represents the hypotenuse, or the longest side, of the triangle.

\tt Step~1:

We know that the hypotenuse is the longest side of the triangle, so that means 9 is c. One side of the triangle is 6, and we have to solve for b. That means 6 is a. We can plug in our values to the formula like this:

\tt a^2+b^2=c^2\\6^2+b+2=9^2\\36+b^2=81

\tt Step~2:

Now that we have our equation down, we know what we have to do next: subtract 81 from 36 to get b².

\tt 81-36=\sqrt{45}

\Large\boxed{\tt Our~final~answer:~b=\sqrt{45} ~(simplified:3\sqrt{5}) }

7 0
3 years ago
Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an i
laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

P(47)=50(3)^{\frac{47}{30} }

P(47)=50(3)^{1.567}

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

750=50(3)^{\frac{t}{30} }

\frac{750}{50}=(3)^{\frac{t}{30} }

(3)^{\frac{t}{n} }=15

Using the property <u>Power</u> <u>Rule</u> of logarithm:

log(3)^{\frac{t}{30} }=log15

\frac{t}{30}log(3)=log15

t=\frac{log15}{log3} .30

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

A(t)=A_{0}e^{kt}

3A_{0}=A_{0}e^{30k}

3=e^{30k}

Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

3 0
3 years ago
PLEASE HELP WITH ALL!!!
Ad libitum [116K]

Answer:

3)x=-9

4)x=-2

5)x=-4

6)x=-5

7)x=-12

8)x=-11

Step-by-step explanation:

7 0
2 years ago
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