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3 years ago

The sum of two numbers is 342. One of the numbers is 252. What is the other number?

Mathematics

2 answers:

jeka943 years ago

4 0

Answer:

Step-by-step explanation:

342-252=90

So, therefore, 252+90=342

Darina [25.2K]3 years ago

3 0

Answer:

Step-by-step explanation:

Since the sum is 342 and we already know the first number is 252 we would take away 252 from 342 to get the amount of the second number.

(342-252=90)

We got 90 and to check we would add 252+90 which is =

(252+90=342)

The answer is 90

I hope this helped:)

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3 years ago

A rectangle has the length of 22 inches less than 7 times the width. If the area of the rectangle is 3197 square inches, find th

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Solution:

Given that, area of the rectangle is 3197 square inches

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Also given that rectangle has the length of 22 inches less than 7 times the width

Length = 7 times width - 22

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$\text {Area of rectangle }=\text { length } \times \text { width }$

Substituting the values we get,

$\begin{array}{l}{3197=(7 W-22)(W)} \\\\ {3197=7 W^{2}-22 W} \\\\ {7 W^{2}-22 W-3197=0}\end{array}$

On solving the above quadratic equation using quadratic formula,

$\text {For the quadratic equation } a x^{2}+b x+c=0 \text { where } a \neq 0$

$x=\frac{-b \pm \sqrt{\left(b^{2}-4 a c\right)}}{2 a}$

$\begin{array}{l}{\text {Here in } 7 \mathrm{W}^{2}-22 \mathrm{W}-3197=0} \\\\ {a=7 ; b=-22 ; c=-3197}\end{array}$

Substituting in above quadratic formula,

$\begin{array}{l}{W=\frac{-(-22) \pm \sqrt{\left((-22)^{2}-4(7)(-3197)\right)}}{2 \times 7}} \\\\ {W=\frac{22 \pm \sqrt{90000}}{14}=\frac{22 \pm 300}{14}} \\\\ {W=\frac{22+300}{14} \text { or } W=\frac{22-300}{14}} \\\\ {W=23 \text { or } W=-19.85}\end{array}$

Since width of rectangle cannot be negative, ignore negative value of "W"

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