All categories

3 years ago

Can someone help with this please

Mathematics

2 answers:

DanielleElmas [232]3 years ago

7 0

Answer:

Step-by-step explanation:

3^8 * 3^4

ـــــــــــــــــــــ

3^2 * 3^8 =

3^(8+4)

ـــــــــــــــــــــ

3^(2+8) =

3^12

ـــــــــــــــــــــ

3^10 =

3^2

crimeas [40]3 years ago

5 0

Answer:

$3^2$

Step-by-step explanation:

$\frac{3^8*\:3^4}{3^2*\:3^8}$

Apply Exponent rule: $a^b\cdot \:a^c=a^{b+c}$

$\frac{3^{12}}{3^8* \:3^2}$

$\frac{3^{12}}{3^{10}}$

Apply exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$3^{12-10}=3^2$

You might be interested in

a wool suit discounted by 30% for a clearance sale, has a price tag of $199. what was the suit's original price

Elena-2011 [213]

Answer:

Step-by-step explanation:

Let the original price be x

The discounted price for a clearance sale = 30% of x

If the price tag after discounting = $199.

Using the relationship to find the original price x

Original price - discounted price = Current price tag after discounting

x - 0.3x = 199

0.7x = 199

Divide both sides by 0.7

0.7x/0.7 = 199/0.7

x = $284.29

<em>Hence the suit's original price is approximately $284.29</em>

<em />

5 0

3 years ago

REALLY NEED HELP

IgorLugansk [536]

You can compare information on up to three different Loan Options at one time. When entering information into the calculator, please use the following guidelines:
Interest Rate is the APR from the loan rate chart. If the loan rate is 6.5% you would type 6.5 into the Interest Rate blank
# of Payments is the number of monthly payments you will make to pay off the loan. For example, if the approximate term of the loan is 4 years or 48 months, you would enter 48 in the # of Payments blank
Principal is the amount of money you want to borrow. If you want to borrow $7,500 you would enter 7500 in the Principal blank
Monthly Payment is the estimated amount of money you will need to pay each month to pay off the loan

6 0

3 years ago

A statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after

lana [24]

Answer:

95% confidence interval estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

(a) Lower Limit = 0.486

(b) Upper Limit = 0.624

Step-by-step explanation:

We are given that a statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after receiving their bachelor's.

She took a random sample of 200 graduates from the class of 1979 and determined their occupations in 1989. She found that 111 persons were still employed primarily as engineers.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of persons who were still employed primarily as engineers = $\frac{111}{200}$ = 0.555

n = sample of graduates = 200

p = population proportion of engineers

<em>Here for constructing 95% confidence interval we have used One-sample z proportion test statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

<u>95% confidence interval for p</u> = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.555-1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } }$ , $0.555+1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } }$ ]