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lilavasa [31]
3 years ago
13

Find the 12th partial sum of ∞∑  (-2i-10)i-1

Mathematics
2 answers:
zvonat [6]3 years ago
8 0
<h2>Answer:</h2>

The 12th partial sum of the given series is:

                                -276

<h2>Step-by-step explanation:</h2>

We are asked to find the 12th partial sum of the series which is given by:

             \sum_{i=1}^{\infty}(-2i-10)

i.e. we have to find the sum of first 12 terms.

i.e.

\sum_{i=1}^{12}(-2i-10)

which could also be simplified by the method:

\sum_{i=1}^{12}(-2i-10)=-2\sum_{i=1}^{12}i-10\sum_{i=1}^{12}1

which is further given by:

\sum_{i=1}^{12}(-2i-10)=-2\times (1+2+3+4+5+6+7+8+9+10+11+12)-10\times (1+1+1+1+1+1+1+1+1+1+1+1)

know we know that:

1+2+3+.....+n=\dfrac{n(n+1)}{2}

i.e.

1+2+3+....+12=\dfrac{12\times 13}{2}\\\\1+2+3+....+12=78

Hence, we get:

\sum_{i=1}^{12}(-2i-10)=-2\times 78-10\times 12\\\\[tex]\sum_{i=1}^{12}(-2i-10)=-156-120\\\\[tex]\sum_{i=1}^{12}(-2i-10)=-276

           Hence, the answer is:  -276

telo118 [61]3 years ago
4 0
Hello,


$\sum_{i=1}^{12}(-2i-10)=-10\sum_{i=1}^{12}1-2\sum_{i=1}^{12}i$

=-120-2*13*12/2=-120-156=-276

 
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Answer:

Step-by-step explanation:

The circular city park has a sidewalk directly through the middle that is 111 - feet long. This means that the diameter of the park is 111 feet.

The formula for determining the the area of a circle is expressed as

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Where

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π is a constant whose value is 3.14

From the information given,

Diameter = 111 feet

Radius = diameter/2 = 111/2 = 55.5 feet.

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Step-by-step explanation:

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Given: <br><br> ∆SPM, PK⊥ SM<br><br> SP = 25, SM = 28, PK = 9<br><br> Find: m∠S, m∠M, PM
nevsk [136]

Answer:

∠S = 21.10°

∠M = 79.45°

PM = 9.16

Step-by-step explanation:

Here Pythagorean theorem and trigonometry suffice to solve our problem.

From the Pythagorean theorem we get:

KM^2+9^2=PM^2 and

(25-KM)^2+9^2=25^2.

We solve for KM in the second equation and get:

(25-KM)=\sqrt{25^2-9^2}

\therefore KM=25-\sqrt{25^2-9^2} =\boxed{1.68}

Now since

SK+KM=25\\\\ SK=\boxed{23.32}

Therefore

{\angle}S=Tan^{-1}(\frac{PK}{SK}) = Tan^{-1}(\frac{9}{23.32})=21.10^o

and

{\angle}M=Tan^{-1}(\frac{PK}{KM}) = Tan^{-1}(\frac{9}{1.68})=79.45^o.

And finally again from the Pythagorean theorem:

PM^2=PK^2+KM^2=9^2+1.68^2

\therefore PM=\sqrt{9^2+1.68^2} =9.16.

Thus,

∠S = 21.10°

∠M = 79.45°

PM = 9.16.

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