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3 years ago

How would you find a answer to x(2)+6

Mathematics

1 answer:

Svetlanka [38]3 years ago

8 0

Multiply then add
2x + 6
8x

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option 1 drop down are: even-odd identity, quotient identity, Pythagorean identity, double-number identity.option 2 drop down ar

motikmotik

Answer:

The equation is given below as

$\frac{\cos2x}{\cos x}=\cos x-\sin x\tan x$

Step 1:

We will work on the left-hand side, we will have

$\begin{gathered} \cos x-\sin x\tan x \\ \text{recall that,} \\ Quoitent\text{ identity is} \\ \tan x=\frac{\sin x}{\cos x} \end{gathered}$

By substituting the identity above, we will have

$\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x}=\cos x-\frac{\sin^2x}{\cos x} \\ \end{gathered}$

Here, we will make use of the quotient identity

Step 2:

By writings an expression, we will have

$\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x} \\ \cos x-\sin x\tan x=\frac{\cos^2x-\sin^2x}{\cos x} \end{gathered}$

Here, we will use the definition of subtraction

$\cos x-\frac{\sin^2x}{\cos x}$

Step 3:

We will apply the double number identity given below

$\begin{gathered} \cos 2\theta=\cos (\theta+\theta)=\cos ^2\theta-\sin ^2\theta \\ \cos 2x=cos(x+x)=\cos ^2x-\sin ^2x \end{gathered}$

By applying this, we will have

$\frac{\cos^2x-\sin^2x}{\cos x}=\frac{\cos2x}{\cos x}$

Here, we will use the double number identity

$\frac{\cos^2x-\sin^2x}{\cos x}$

5 0

1 year ago

Determine the value of y when x=15 if y=6 when x =30

Vladimir79 [104]

6+9=15
y+9=x
x=30
y+9=30
y=21

6 0

3 years ago

How many nanometers in 66cm

makvit [3.9K]

66cm is equal to 6.6e+8 nanometers.

4 0

3 years ago

I need help on my transformations lesson, I’m very confused help

kkurt [141]

It's a reflection :) look up colin Dodds geometric transformations that's how I learned it it's a fun song

5 0

3 years ago

For f(x) = x2 + 2x + 3, and g(x) = x2 + 5, Find F(g(2)).

Paraphin [41]

Answer:

f(g(2)) = 102

Step-by-step explanation:

f(x) and f(g(2))

As we can see, we can find g(2) and substitute this value into

f(x)=x² + 2x + 3 instead of x.

g(x) = x² + 5, g(2) = 2² + 5 = 9

f(x)=x² + 2x + 3

f(9)=9² + 2*9 + 3= 102

5 0

3 years ago