How would you find a answer to x(2)+6

Hi, please help me out with this math problem.

GalinKa [24]

9514 1404 393

Answer:

x - 4

Step-by-step explanation:

The expression simplifies to ...

$\sqrt{x^2-8x+16}=\sqrt{(x-4)^2}=|x-4|$

For x ≥ 4, the argument of the absolute value function is non-negative, so it remains unchanged. The simplified expression is ...

x - 4 . . . . for x ≥ 4

6 0

3 years ago

Find the simple interest for $2,800 at 4% for 4 yrs

SVEN [57.7K]

It would be 2800*0.04*4. Your final answer will be $448

6 0

3 years ago

I NEED THIS BADLY <br> WILL MARK BRAINLYIST

stiks02 [169]

What’s the question?

5 0

3 years ago

A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014$

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

7 0

3 years ago

Which formula gives the x-coordinates of the maximum values for y = cos(x)?

solong [7]

We have been given a function $y=\cos(x)$ . We are asked to find the formula which gives the x-coordinates of the maximum values for given function.

We know that cosine function oscillates between $-1$ and 1 that is minimum value of cosine is $-1$ and maximum value is $1$ .

We also know that $\cos(0)=1$ and after period of cosine is $2\pi$ . This means after every $2\pi$ , we will get to $1$ .

So maximum of cosine is $2\pi n$ , where n is an integer.

Therefore, our required formula is $2\pi n$ , where, $n=0,\pm 1,\pm 2,\pm3,...$

7 0

3 years ago