All categories

3 years ago

HELP ME QUICK

Mathematics

1 answer:

Colt1911 [192]3 years ago

8 0

Explanation:
First equation can be arranged as:
4
x
−
7
=
y
Put this y into the second equation (instead of y use
4
x
−
7
):
2
x
−
3
(
4
x
−
7
)
=
−
9
2
x
−
12
x
+
21
=
−
9
−
10
x
=
−
9
−
21
−
10
x
=
−
30
x
=
3
y can be obtained using the first equation:
y
=
4
x
−
7
y
=
(
4
×
3
)
−
7
y
=
12
−
7
y
=
5
Your solution
x
=
3

You might be interested in

Show that the maximum rate of change, with respect to radius, of the volume of a deflating balloon is four times the sphere's in

dmitriy555 [2]

Step-by-step explanation:

Let's say R is the initial radius of the sphere, and r is the radius at time t.

The volume of the sphere at time t is:

V = 4/3 π r³

Taking derivative with respect to radius:

dV/dr = 4π r²

This is a maximum when r is a maximum, which is when r = R.

(dV/dr)max = 4π R²

This is 4 times the sphere's initial great circle area, but not the great circle circumference. The problem statement contains an error.

7 0

3 years ago

the width of a rectangle is 12 cm less than the length the perimeter is 156 cm. Find the length and width

-BARSIC- [3]

We can write this question as an equation to solve it. Using L for length and W for width we know that

L+L+W+W=perimeter
2L+2W=perimeter

We can put the value of the perimeter into this

2L+2W=156cm

Next, we have to make sure all the terms (letters) are the same so we can solve it. This means we have to rewrite either the length or width in terms of the other.

We know the width is 12cm less than the length, which is the same as saying L-12
Then we substitute this into the equation and solve L

2L+2(L-12)=156
2L+2L-24=156
4L-24=156
4L=180
L=45cm

Next we use this value to find W.
45-12=33
W=33cm

4 0

4 years ago

Silas tosses a football with an initial velocity of 10 ft/s from an initial height of 6 ft. What is the maximum height the ball

SSSSS [86.1K]

Sounds like a physics problem

basically we can simlpify it to this:
we toss something straight up with initial velocity 10ft/sec, assuming gravity kicks in, what is max height?

we can use the kinematic equation $v_{f}^2=v_{0}^2+2ad$
$v_f$ is final velocity
$v_0$ is initial velocity
a is acceleration due to gravity
d=distance traveled

if we say he tosses it straight up then when it reaches max height, $v_f=0$
and $v_0=10 \frac{ft}{s}$

and we know that $a=-32.174 \frac{ft}{s^2}$

so solving for d

 $v_{f}^2=v_{0}^2+2ad$
 $v_{f}^2-v_{0}^2=2ad$
 $\frac{v_{f}^2-v_{0}^2}{2a}=d$
plug the numbers in

$\frac{(0)^2-(10 \frac{ft}{s})^2}{2(-32.174 \frac{ft}{s^2})}=d$
$1.5540498539193137315845092310561 ft=d$

we add that to the initial 6ft
so total of 7.5540498539193137315845092310561 ft max height
about 7.6ft

7 0

3 years ago

Explain how to use the distributive property to find the product (3) ( 4 1 5 ) .

shusha [124]

We will break down the 415
3(415) =
3(400) + 3(10) + 3(5) =
1200 + 30 + 15 =
1245

7 0

4 years ago

Read 2 more answers

the lines on a 2 cup liquid measuring cup divide each cup into eighths. if you measure 1 3/4 cups of water between which two qua

guajiro [1.7K]

Answer:

1 3/4 cups is between the 13th and 15th lines from the bottom.

Step-by-step explanation:

The bottom of the cup has no line and corresponds to 0 eights.

1st line up: 1/8 cup

2nd line up: 2/8 cup this is also called 1/4 cup

3rd line up: 3/8 cup

4th line up: 4/8 cup this is also called 1/2 cup

5th line up: 5/8 cup

6th line up: 6/8 cup this is also called 3/4 cup

7th line up: 7/8 cup

8th line up: 8/8 cup this is also called 1 cup

9th line up: 9/8 cup

10th line up: 10/8 cup this is also called 1 1/4 cup

11th line up: 1 3/8 cup

12th line up: 1 4/8 cup this is also called 1 1/2 cup

13th line up: 1 5/8 cup

14th line up: 1 6/8 cup this is also called 1 3/4 cup

15th line up: 1 7/8 cup

16th line up: 1 8/8 cup this is also called 2 cups

1 3/4 cups is between the 13th and 15th lines from the bottom.

7 0

3 years ago