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3 years ago

14

The sweet sweet shop charges $8.45 for a pound of chocolate covered almonds. If Britain buys 1.5 pounds of the almonds, how much

will she have to pay?

1 answer:

choli [55]3 years ago

5 0

Answer:

$12.68

Step-by-step explanation:

Multiply the price of one pound by the amount of pounds you're buying,

8.45 x 1.5

= 12.675

Round up

= 12.68

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The winner of a raffle will receive 3/4 of the $530.40 raised from raffle ticket sales.How much money will the winner get?

Setler79 [48]

$money\ for\ winner\ =\frac{3}{4}*raffle\ ticket\ sales\\\\
money\ for\ winner=\frac{3}{4}*530.40\\\\
money\ for\ winner=\frac{3}{4}*530.40=\frac{1591.2}{4}=397,8$\\\\
Winner\ will\ get\ 397.8\$.

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3 years ago

What is the measure of each interior angle of the regular polygon pictured below? If necessary, round to the nearest tenth.

sesenic [268]

Answer:

144

Step-by-step explanation:

The measure of each interior angle formula:

$\frac{180(n-2)}{n} \\\\\frac{180(10-2)}{10} \\\\\frac{180(8)}{10} \\\\\frac{1440}{10} \\\\144$

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2 years ago

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When engaging in weight-control (fitness/fat burning) types of exercise, a person is expected to attain about 60% of their maxim

Nimfa-mama [501]

Answer:

a) <em> standard error of the mean =10.06</em>

<em>b) The margin of error = 17.3982</em>

<em>c) 95% of confidence intervals are </em>

<em></em> $(89.6018 ,124.3982)$ <em></em>

<em>d) Lower limit of 95% of confidence interval = 89.6018</em>

<em>upper limit of 95% of confidence interval = 124.3982</em>

<em>The Population mean is lies between in these intervals</em>

<u>Step-by-step explanation:</u>

<u><em>Step(i)</em></u><u>:-</u>

Given sample size 'n' = 20

Given sample mean was found to be 107 bpm with a standard deviation of 45 bpm.

<em>Sample mean </em> $x^{-} = 107 bpm$ <em></em>

<em>Sample standard deviation (S) = 45 bpm</em>

<em>a) standard error of the mean is determined by</em>

<em> </em> $S.E = \frac{S}{\sqrt{n} } = \frac{45}{\sqrt{20} }$ <em></em>

<em> S.E = 10.06</em>

<em>b) The margin of error is determined by</em>

<em></em> $M.E = \frac{t_{\alpha } X S }{\sqrt{n} }$ <em></em>

<em>The degrees of freedom ν </em> $= n-1 =20-1=19$ <em></em>

<em> </em> $t_{\alpha } = 1.729$

<em></em> $M.E = \frac{1.729X 45}{\sqrt{20} }$ <em></em>

<em></em> $M.E = \frac{77.805 }{4.472 } = 17.3982$ <em></em>

<em>c) 95% of confidence intervals are determined by</em>

<em></em> $(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} + t_{\alpha } \frac{S}{\sqrt{n} } )$ <em></em>

<em></em> $(107 - 1.729\frac{45}{\sqrt{20} } , 107 + 1.729\frac{45}{\sqrt{20} } )$ <em></em>

<em></em> $(107 - 17.3982 } , 107 +17.3982 )$ <em></em>

<em></em> $(89.6018 ,124.3982)$ <em></em>

<em>d) </em>

<em>Lower limit of 95% of confidence interval = 89.6018</em>

<em>upper limit of 95% of confidence interval = 124.3982</em>

<em>The Population mean is lies between in these intervals</em>

<em></em>

<em></em>

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3 years ago

a 1 =− 3 1 a, start subscript, 1, end subscript, equals, minus, start fraction, 1, divided by, 3, end fraction a i = a i − 1

MrRa [10]

Answer:

$S_{75}=-506.888989761$ X 10^{32}$

Step-by-step explanation:

Given the sequence

$a_1=-\dfrac{1}{3}\\ a_i=a_{i-1}\cdot (-3)$

$a_2=a_{2-1}\cdot (-3)=a_1 \cdot (-3) = -\dfrac{1}{3}\cdot (-3)=1\\a_3=a_{3-1}\cdot (-3)=a_2 \cdot (-3) = 1 \cdot (-3)=-3\\a_4=a_{4-1}\cdot (-3)=a_3 \cdot (-3) = -3 \cdot (-3)=9\\$

Therefore the sequence is:

$-\dfrac{1}{3}, 1, -3, 9, ...$

This is a geometric sequence where the:

First Term, $a_1=-\dfrac{1}{3}$

Common ratio, r =-3

We want to determine the sum of the first 75 terms.

For a geometric sequence, the sum:

$S_n=\dfrac{a_1(1-r^n)}{1-r} \\$

Therefore:

$S_{75}=\dfrac{-\dfrac{1}{3}(1-(-3)^{75})}{1-(-3)} \\\\=\dfrac{-(1-(-3)^{75})}{4*3}\\\\S_{75}=\dfrac{(-3)^{75}-1}{12}\\\\S_{75}=-506.888989761$ X 10^{32}$

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3 years ago

11. Tyler told his friend this riddle: "I am thinking of a number. Three times my number plus twice

guapka [62]

Answer:

3x+2x=20

5x=20

x=4

Tyler's number is 4.

Step-by-step explanation:

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3 years ago

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